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Anissh J Class 11 Tuition trainer in Bangalore

Anissh J

Physics geek

Electronic City, Bangalore, India - 560100.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I have strong fundamental knowledge and interest in Physics. Have scored 199/200 in higher secondary(12th) board exam and completed mechanical engineering which actually comprises of physical science with 7.9 CGPA from Government college of engineering.
Have strong understanding of basics so that I can able to explain the topics in different ways to ensure the listener is interested. Any queries give me an email and text through whatsapp i am happy to respond back at the earliest. Happy learning!!!!!

Languages Spoken

Tamil Mother Tongue (Native)

English Proficient

Education

Anna University 2013

Bachelor of Engineering (B.E.)

Address

Electronic City, Bangalore, India - 560100

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

ISC/ICSE, IGCSE, CBSE, International Baccalaureate, State

IB Subjects taught

Physics

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

IGCSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

ISC/ICSE, IGCSE, CBSE, International Baccalaureate, State

IB Subjects taught

Physics

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

IGCSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

ISC/ICSE, IGCSE, CBSE and others

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 11 Tuition and Class 12 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 5 years.

Answers by Anissh J (10)

Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

Great question. Young's modulus is a material/intrinsic property of the material and is constant regardless of the change in dimension of the test specimen. Y = Stress/ Strain = F*L/A*dl Assume if you change the L to L/2 and r to r/2 i.e A to A/4 and Force required to get the same extension is also F/2,... ...more

Great question. Young's modulus is a material/intrinsic property of the material and is constant regardless of the change in dimension of the test specimen.

Y = Stress/ Strain = F*L/A*dl

Assume if you change the L to L/2 and r to r/2 i.e A to A/4 and Force required to get the same extension is also F/2, above equation becomes

Y = 4*F*L/4*A*dl = F*L/A*dl ( Same as above)

Happy learning!!!

Answers 1 Comments
Dislike Bookmark

Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

Acceleration = Velocity/time i.e rate of change of velocity. So if we differentiate Velocity w.r.t time we will get Acceleration. dA = dV/dt = 2(a2) So acceleration = 2(a2)
Answers 4 Comments
Dislike Bookmark

Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

Velocity is the rate of change of displacement i.e Displacement/time. Vector quantity Speed is the rate of change of distance i.e Distance/time. Scalar quantity Let me give a quick example to understand the concept. Say a person in walking in his community with 1m/s in the east direction, 1 m/s in the... ...more

Velocity is the rate of change of displacement i.e Displacement/time. Vector quantity

Speed is the rate of change of distance i.e Distance/time. Scalar quantity

Let me give a quick example to understand the concept. Say a person in walking in his community with 1m/s in the east direction, 1 m/s in the north direction, 1m/s in west direction and 1m/s in south direction. Since velocity is a vector quantity and there is a change in direction velocity varies but the speed is not varying being a scalar quantity.

Happy learning!!!

Answers 1 Comments
Dislike Bookmark

Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

To understand the concept of Speed and velocity we need to first understand what displacement and distance are. Displacement:- Overall change in position relative to the start point e.g. How much it is moved from the start point. It is a vector quantity. Distance:- How much covered in total. It is a... ...more

To understand the concept of Speed and velocity we need to first understand what displacement and distance are. 

Displacement:- Overall change in position relative to the start point e.g. How much it is moved from the start point. It is a vector quantity.

Distance:- How much covered in total. It is a scalar quantity.

So by the above definition, Distance is always equal to greater than displacement. Let me give a small example to understand the concept clearly.

Suppose you are running a 400m race in the track, distance covered is 400m & displacement is 0 because you have reached the start point and hence no change in position.

Speed = Distance/time and Velocity = Displacement/time 

Since, Distance >= Displacement, Always Speed >= velocity.

Happy learning!!!

Answers 1 Comments
Dislike Bookmark

Answered on 26/09/2018 Learn CBSE/Class 11/Science/Physics

(i) It is obvious from the graph that since Velocity (v) lies on Y-axis and line B has the highest point along Y-axis it is having the higher velocity under comparison (ii) The reason is Slope. Slope = y/x and if you calculate for both the curve you will find the slope for line B more compared to Line... ...more

(i) It is obvious from the graph that since Velocity (v) lies on Y-axis and line B has the highest point along Y-axis it is having the higher velocity under comparison

(ii) The reason is Slope. Slope = y/x and if you calculate for both the curve you will find the slope for line B more compared to Line A for the same X and Y co-ordinates

Answers 3 Comments
Dislike Bookmark

Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

ISC/ICSE, IGCSE, CBSE, International Baccalaureate, State

IB Subjects taught

Physics

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

IGCSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

ISC/ICSE, IGCSE, CBSE, International Baccalaureate, State

IB Subjects taught

Physics

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

IGCSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics

No Reviews yet!

Answers by Anissh J (10)

Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

Great question. Young's modulus is a material/intrinsic property of the material and is constant regardless of the change in dimension of the test specimen. Y = Stress/ Strain = F*L/A*dl Assume if you change the L to L/2 and r to r/2 i.e A to A/4 and Force required to get the same extension is also F/2,... ...more

Great question. Young's modulus is a material/intrinsic property of the material and is constant regardless of the change in dimension of the test specimen.

Y = Stress/ Strain = F*L/A*dl

Assume if you change the L to L/2 and r to r/2 i.e A to A/4 and Force required to get the same extension is also F/2, above equation becomes

Y = 4*F*L/4*A*dl = F*L/A*dl ( Same as above)

Happy learning!!!

Answers 1 Comments
Dislike Bookmark

Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

Acceleration = Velocity/time i.e rate of change of velocity. So if we differentiate Velocity w.r.t time we will get Acceleration. dA = dV/dt = 2(a2) So acceleration = 2(a2)
Answers 4 Comments
Dislike Bookmark

Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

Velocity is the rate of change of displacement i.e Displacement/time. Vector quantity Speed is the rate of change of distance i.e Distance/time. Scalar quantity Let me give a quick example to understand the concept. Say a person in walking in his community with 1m/s in the east direction, 1 m/s in the... ...more

Velocity is the rate of change of displacement i.e Displacement/time. Vector quantity

Speed is the rate of change of distance i.e Distance/time. Scalar quantity

Let me give a quick example to understand the concept. Say a person in walking in his community with 1m/s in the east direction, 1 m/s in the north direction, 1m/s in west direction and 1m/s in south direction. Since velocity is a vector quantity and there is a change in direction velocity varies but the speed is not varying being a scalar quantity.

Happy learning!!!

Answers 1 Comments
Dislike Bookmark

Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

To understand the concept of Speed and velocity we need to first understand what displacement and distance are. Displacement:- Overall change in position relative to the start point e.g. How much it is moved from the start point. It is a vector quantity. Distance:- How much covered in total. It is a... ...more

To understand the concept of Speed and velocity we need to first understand what displacement and distance are. 

Displacement:- Overall change in position relative to the start point e.g. How much it is moved from the start point. It is a vector quantity.

Distance:- How much covered in total. It is a scalar quantity.

So by the above definition, Distance is always equal to greater than displacement. Let me give a small example to understand the concept clearly.

Suppose you are running a 400m race in the track, distance covered is 400m & displacement is 0 because you have reached the start point and hence no change in position.

Speed = Distance/time and Velocity = Displacement/time 

Since, Distance >= Displacement, Always Speed >= velocity.

Happy learning!!!

Answers 1 Comments
Dislike Bookmark

Answered on 26/09/2018 Learn CBSE/Class 11/Science/Physics

(i) It is obvious from the graph that since Velocity (v) lies on Y-axis and line B has the highest point along Y-axis it is having the higher velocity under comparison (ii) The reason is Slope. Slope = y/x and if you calculate for both the curve you will find the slope for line B more compared to Line... ...more

(i) It is obvious from the graph that since Velocity (v) lies on Y-axis and line B has the highest point along Y-axis it is having the higher velocity under comparison

(ii) The reason is Slope. Slope = y/x and if you calculate for both the curve you will find the slope for line B more compared to Line A for the same X and Y co-ordinates

Answers 3 Comments
Dislike Bookmark

Contact

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Anissh J describes himself as Physics geek. He conducts classes in Class 11 Tuition and Class 12 Tuition. Anissh is located in Electronic City, Bangalore. Anissh takes at students Home and Online Classes- via online medium. He has 5 years of teaching experience . Anissh has completed Bachelor of Engineering (B.E.) from Anna University in 2013. HeĀ is well versed in Tamil and English.

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