Sector-46, Chandigarh, India - 160047.
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Chaudhary ranbir singh university Pursuing
Bachelor of Education (B.Ed.)
Delhi university 2016
Bachelor of Science (B.Sc.)
Sector-46, Chandigarh, India - 160047
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
2
Board
CBSE
CBSE Subjects taught
English, EVS, Science, Computers, Mathematics, Social Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
2
Board
CBSE
CBSE Subjects taught
English, Science, EVS, Mathematics, Social Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
2
Board
CBSE
CBSE Subjects taught
English, Science, EVS, Mathematics, Social Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
2
Board
CBSE
CBSE Subjects taught
English, Science, EVS, Mathematics, Social Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics, Science, Social science, English
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics, Science, Social science, English
Taught in School or College
No
1. Which school boards of Class 1-5 do you teach for?
CBSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and Class I-V Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 2 years.
Answered on 17/01/2018 Learn CBSE/Class 10/Mathematics
On Squaring and subtracting,
we get m^2-n^2=4tanlsinlNow, taking rhs, on multiplying 1*2,
we get mn=tan^2l- sin^2l( by property of a^2-b^2) Again, by changing tan into sin cos we get, mn=tan^2lsin^2lTaking under root, we get √ mn=tanlsinl
Hence proved!
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
2
Board
CBSE
CBSE Subjects taught
English, EVS, Science, Computers, Mathematics, Social Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
2
Board
CBSE
CBSE Subjects taught
English, Science, EVS, Mathematics, Social Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
2
Board
CBSE
CBSE Subjects taught
English, Science, EVS, Mathematics, Social Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
2
Board
CBSE
CBSE Subjects taught
English, Science, EVS, Mathematics, Social Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics, Science, Social science, English
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE
CBSE Subjects taught
Mathematics, Science, Social science, English
Taught in School or College
No
Answered on 17/01/2018 Learn CBSE/Class 10/Mathematics
On Squaring and subtracting,
we get m^2-n^2=4tanlsinlNow, taking rhs, on multiplying 1*2,
we get mn=tan^2l- sin^2l( by property of a^2-b^2) Again, by changing tan into sin cos we get, mn=tan^2lsin^2lTaking under root, we get √ mn=tanlsinl
Hence proved!
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