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Chirag Palan Class 11 Tuition trainer in Chennai

Chirag Palan

IIT JEE Trainer

Indian Institute Of Technology, Chennai, India - 600036.

1 review

2 Students

Contact
Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Education

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Overview

6 years of teaching experience of IIT JEE
I am teaching IIT JEE (Mains and advanced) as well as other engineering entrance exam mathematics from last four years.
My students got admission at IIT madras, bits, manipal and other reputed engineering Institutions.
I also provide necessary information for the admission in various Institutions.
I am currently perusing M S in IIT madras.
I also provide all the study materials and test series for the aspirants.

Languages Spoken

Gujarati

Hindi

English

Marathi

Tamil

Education

IIT-Madras 2016

Research scholar, Mathematical modelling

Address

Indian Institute Of Technology, Chennai, India - 600036

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Email Verified

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Teaches

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

CBSE, State

CBSE Subjects taught

Physics, Political Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics, Mathematics

Teaching Experience in detail in Class 11 Tuition

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

CBSE, State

CBSE Subjects taught

Physics, Political Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics, Mathematics

Teaching Experience in detail in Class 12 Tuition

Reviews (1)

5 out of 5 1 review

pallan c. https://p.urbanpro.com/tv-prod/member/photo/130166-small.jpg Indian Institute Of Technology
5.0051
pallan c.
S

IIT JEE Coaching

"I have taken personal classes for iit jee from Mr.chirag he is excellent in teaching from the basics, also his excellence in explaining concept through the physical application of maths is just. I have come across many other tutors but most of them are more or less formula based. In last I just want to say Mr.Chirac thank for your support "

Have you attended any class with Chirag?

FAQs

1. Which school boards of Class 12 do you teach for?

CBSE, State

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 11 Tuition and Class 12 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 5 years.

Contact

Answers by Chirag (18)

Answered on 23/11/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC) CBSE/Class 12/Mathematics

Find the equation to the hyperbola whose asymptotes are the straight lines x + 3y -- 1= 0 and 2x -- y... ...more
Find the equation to the hyperbola whose asymptotes are the straight lines x + 3y – 1= 0 and 2x – y + 7 = 0, and which passes through the point (1, 2)?

Let equation of the hyperbola is (x-h)^2/a^2+(y-b)^2/b^2 and its asymptotes are given by:- y=+or-(b/a)(x-h)+k. You can compare your equations with this and find relevant values of a, b, h, k and substitute in equation of hyperbola.
Answers 2 Comments
Dislike Bookmark

Answered on 23/11/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC) CBSE/Class 12/Mathematics

Find the equation to the hyperbola whose asymptotes are the straight lines x + 3y -- 1= 0 and 2x -- y... ...more
Find the equation to the hyperbola whose asymptotes are the straight lines x + 3y – 1= 0 and 2x – y + 7 = 0, and which passes through the point (1, 2)?

Asymptotes are nothing but tangents at infinity take equation of tangents and solve it.
Answers 2 Comments
Dislike Bookmark

Answered on 23/11/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC) CBSE/Class 12/Mathematics

What is the equation of rectangular hyperbola?

xy = c.
Answers 17 Comments
Dislike Bookmark

Answered on 20/12/2015 Learn Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching

Hello there What was the format of exam JEE (Advanced)  2014? Anyone can give me the format? Thanks

kindly refer to jee website for updates
Answers 45 Comments
Dislike Bookmark

Answered on 20/12/2015 Learn Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching

Please tell some good books Mathematics for IIT-JEE Mains for class PUC?

IIT jee mathematics for jee mains and advance by M L Khanna
Answers 19 Comments
Dislike Bookmark

Contact

View All

Teaches

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

CBSE, State

CBSE Subjects taught

Physics, Political Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics, Mathematics

Teaching Experience in detail in Class 11 Tuition

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

CBSE, State

CBSE Subjects taught

Physics, Political Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Physics, Mathematics

Teaching Experience in detail in Class 12 Tuition

5 out of 5 1 review

pallan c.
S

IIT JEE Coaching

"I have taken personal classes for iit jee from Mr.chirag he is excellent in teaching from the basics, also his excellence in explaining concept through the physical application of maths is just. I have come across many other tutors but most of them are more or less formula based. In last I just want to say Mr.Chirac thank for your support "

Have you attended any class with Chirag?

Answers by Chirag Palan (18)

Answered on 23/11/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC) CBSE/Class 12/Mathematics

Find the equation to the hyperbola whose asymptotes are the straight lines x + 3y -- 1= 0 and 2x -- y... ...more
Find the equation to the hyperbola whose asymptotes are the straight lines x + 3y – 1= 0 and 2x – y + 7 = 0, and which passes through the point (1, 2)?

Let equation of the hyperbola is (x-h)^2/a^2+(y-b)^2/b^2 and its asymptotes are given by:- y=+or-(b/a)(x-h)+k. You can compare your equations with this and find relevant values of a, b, h, k and substitute in equation of hyperbola.
Answers 2 Comments
Dislike Bookmark

Answered on 23/11/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC) CBSE/Class 12/Mathematics

Find the equation to the hyperbola whose asymptotes are the straight lines x + 3y -- 1= 0 and 2x -- y... ...more
Find the equation to the hyperbola whose asymptotes are the straight lines x + 3y – 1= 0 and 2x – y + 7 = 0, and which passes through the point (1, 2)?

Asymptotes are nothing but tangents at infinity take equation of tangents and solve it.
Answers 2 Comments
Dislike Bookmark

Answered on 23/11/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC) CBSE/Class 12/Mathematics

What is the equation of rectangular hyperbola?

xy = c.
Answers 17 Comments
Dislike Bookmark

Answered on 20/12/2015 Learn Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching

Hello there What was the format of exam JEE (Advanced)  2014? Anyone can give me the format? Thanks

kindly refer to jee website for updates
Answers 45 Comments
Dislike Bookmark

Answered on 20/12/2015 Learn Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching

Please tell some good books Mathematics for IIT-JEE Mains for class PUC?

IIT jee mathematics for jee mains and advance by M L Khanna
Answers 19 Comments
Dislike Bookmark

Contact

Load More

Chirag Palan describes himself as IIT JEE Trainer. He conducts classes in Class 11 Tuition and Class 12 Tuition. Chirag is located in Indian Institute Of Technology, Chennai. Chirag takes at students Home. He has 5 years of teaching experience . Chirag has completed Research scholar, Mathematical modelling from IIT-Madras in 2016. He is well versed in Gujarati, Hindi, English, Marathi and Tamil. Chirag has got 1 reviews till now with 100% positive feedback.

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