Hauz Khas, Delhi, India - 110016.
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Hindi Mother Tongue (Native)
English Basic
UPTU 2015
Bachelor of Technology (B.Tech.)
Hauz Khas, Delhi, India - 110016
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
3
Engineering Entrance Exams
IIT JEE Coaching Classes
IITJEE Coaching
IIT JEE Advanced Coaching, IIT JEE Foundation Course, IIT JEE Crash Course, IIT JEE Mains Coaching, IIT JEE Integrated Coaching
Type of class
Crash Course, Regular Classes
IIT-JEE Subjects
Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
4
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Physics
CBSE Subjects taught
Physics
Experience in School or College
I have been teaching since 4 years.
Taught in School or College
Yes
State Syllabus Subjects taught
Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
4
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Physics
CBSE Subjects taught
Physics
Experience in School or College
I have been teaching since 4 years.
Taught in School or College
Yes
State Syllabus Subjects taught
Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
State, CBSE, ICSE
CBSE Subjects taught
Science
ICSE Subjects taught
Physics
Experience in School or College
I have been teaching since 4 years.
Taught in School or College
Yes
State Syllabus Subjects taught
Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
4
Experience in School or College
I have teached in Engineering Colleges.
1. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 9 Tuition and Engineering Entrance Coaching Classes.
2. Do you provide a demo class?
Yes, I provide a free demo class.
3. How many years of experience do you have?
I have been teaching for 3 years.
Answered on 25/06/2019 Learn Tuition
x³ + y³ + z³ - 3xyz = (x + y + z) (x² + y² + z² - xy - yz - zx)
since we have x² + y² + z² = xy + yz + zx
x³ + y³ + z³ - 3xyz = 0
x³ + y³ + z³ = 3xyz
Answered on 25/06/2019 Learn Tuition
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
3
Engineering Entrance Exams
IIT JEE Coaching Classes
IITJEE Coaching
IIT JEE Advanced Coaching, IIT JEE Foundation Course, IIT JEE Crash Course, IIT JEE Mains Coaching, IIT JEE Integrated Coaching
Type of class
Crash Course, Regular Classes
IIT-JEE Subjects
Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
4
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Physics
CBSE Subjects taught
Physics
Experience in School or College
I have been teaching since 4 years.
Taught in School or College
Yes
State Syllabus Subjects taught
Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
4
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Physics
CBSE Subjects taught
Physics
Experience in School or College
I have been teaching since 4 years.
Taught in School or College
Yes
State Syllabus Subjects taught
Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
State, CBSE, ICSE
CBSE Subjects taught
Science
ICSE Subjects taught
Physics
Experience in School or College
I have been teaching since 4 years.
Taught in School or College
Yes
State Syllabus Subjects taught
Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
4
Experience in School or College
I have teached in Engineering Colleges.
Answered on 25/06/2019 Learn Tuition
x³ + y³ + z³ - 3xyz = (x + y + z) (x² + y² + z² - xy - yz - zx)
since we have x² + y² + z² = xy + yz + zx
x³ + y³ + z³ - 3xyz = 0
x³ + y³ + z³ = 3xyz
Answered on 25/06/2019 Learn Tuition
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