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Gyan Sagar Class 10 trainer in Delhi

Gyan Sagar

Sitapuri Sitapuri Part 2, Delhi, India - 110045.

Gyan Sagar - Intro Video
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Education

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Overview

I'm a mathematics teacher for foundation class. I'm giving home/online/offline tuition since 2016.I'm certified in teaching NTSE, OLYMPIAD, ICSE/CBSE/STATE BOARD students.I have degree in B.E from Karnatka. I have an total experience of 5+ years in teaching.

Intro Video

  • Class 10 Tuition

Languages Spoken

Hindi Proficient

English Proficient

Education

Siddaganga Institute of Technology 2016

Bachelor of Engineering (B.E.)

Address

Sitapuri Sitapuri Part 2, Delhi, India - 110045

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Teaches

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

5

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 5 years.

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Answers by Gyan Sagar (1)

Answered on 20/04/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic +1 Tuition

At present , the ratio between the ages of P and Q is 5:7 respectively. If the difference between Q's... ...more

At present , the ratio between the ages of P and Q is 5:7 respectively. If the difference between Q's present age and P's age after 6years is 2 ,what is the total age of P's and Q's present age

 

Let present age of P and Q be 5x and 7x years respectively. After 6 years, Q's age =(7x+6) years, P's age=(5x+6) years. According to question, (7x+6) -(5x+6) =2 7x+6-5x-6=2 2x=2 X=2/2 X=1 P's present age=5 years Q's present age=7 years Total age(P's+Q's) =5+7=12 years ...more

Let present age of P and Q be 5x and 7x years respectively. 

After 6 years, 

Q's age =(7x+6) years, 

P's age=(5x+6) years. 

According to question, 

(7x+6) -(5x+6) =2

7x+6-5x-6=2

2x=2

X=2/2

X=1

P's present age=5 years

Q's present age=7 years

Total age(P's+Q's) =5+7=12 years 

 

Answers 353 Comments
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Teaches

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

5

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

No Reviews yet!

Answers by Gyan Sagar (1)

Answered on 20/04/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic +1 Tuition

At present , the ratio between the ages of P and Q is 5:7 respectively. If the difference between Q's... ...more

At present , the ratio between the ages of P and Q is 5:7 respectively. If the difference between Q's present age and P's age after 6years is 2 ,what is the total age of P's and Q's present age

 

Let present age of P and Q be 5x and 7x years respectively. After 6 years, Q's age =(7x+6) years, P's age=(5x+6) years. According to question, (7x+6) -(5x+6) =2 7x+6-5x-6=2 2x=2 X=2/2 X=1 P's present age=5 years Q's present age=7 years Total age(P's+Q's) =5+7=12 years ...more

Let present age of P and Q be 5x and 7x years respectively. 

After 6 years, 

Q's age =(7x+6) years, 

P's age=(5x+6) years. 

According to question, 

(7x+6) -(5x+6) =2

7x+6-5x-6=2

2x=2

X=2/2

X=1

P's present age=5 years

Q's present age=7 years

Total age(P's+Q's) =5+7=12 years 

 

Answers 353 Comments
Dislike Bookmark

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Gyan Sagar conducts classes in Class 10 Tuition. Gyan is located in Sitapuri Sitapuri Part 2, Delhi. Gyan takes at students Home and Regular Classes- at his Home. He has 5 years of teaching experience . Gyan has completed Bachelor of Engineering (B.E.) from Siddaganga Institute of Technology in 2016. He is well versed in Hindi and English.

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