Jamia Nagar, Delhi, India - 110025.
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English Mother Tongue (Native)
Hindi Mother Tongue (Native)
Jamia millia islamia new delhi 2019
Master of Science (M.Sc.)
Jamia Nagar, Delhi, India - 110025
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
CBSE, ISC/ICSE
ISC/ICSE Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE, State, ICSE
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
2
Board
CBSE, State, ISC/ICSE
ISC/ICSE Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
System Design & Computer Architecture
BTech Branch
BTech Electrical & Electronics
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BSc Tuition
1
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BSc Branch
BSc Mathematics
BSc Mathematics Subjects
Algebra, Calculus, Differential Equations and Mathematical Modelling, Analysis
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BCA Tuition
1
BCA Subject
Mathematics
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BA Tuition
2
Field tutored for
Mathematics
BA Mathematics Subjects
Algebra
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
1. Which school boards of Class 12 do you teach for?
CBSE and ISC/ICSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach BA Tuition, BCA Tuition, BSc Tuition, BTech Tuition, Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 2 years.
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Integrals/NCERT Solutions/Exercise 7.5
Let
On solving
A = 1, B = -5, C = 4
Answered on 04/09/2019 Learn CBSE/Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.2
Let f(x)=cos(sinx),
u(x)=sinx , v(t)=cost
Where t=u(x)=sinx
Differentiating it
Since. By chain rule,
Answered on 02/09/2019 Learn CBSE/Class 12/Mathematics/Unit III: Calculus/NCERT Solutions/Exercise 2.1
Answered on 02/09/2019 Learn CBSE/Class 12/Mathematics/Unit III: Calculus/NCERT Solutions/Exercise 2.1
Let tan‾(1)=x
tan(x)=1=tan(π÷4)=π÷4,
x=π÷4;
cos¯(-1÷2)=y
cos(y)=-1÷2=cos(2π÷3)
y=2π÷3;
sin¯(-1÷2)=z⇒sin(z)=-1÷2=sin(-π÷6)
z=-π÷6;
So..........put value of x,y,z.......
π÷4+2π÷3-π÷6=9π÷12=3π÷4....
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
CBSE, ISC/ICSE
ISC/ICSE Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE, State, ICSE
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
2
Board
CBSE, State, ISC/ICSE
ISC/ICSE Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
System Design & Computer Architecture
BTech Branch
BTech Electrical & Electronics
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BSc Tuition
1
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BSc Branch
BSc Mathematics
BSc Mathematics Subjects
Algebra, Calculus, Differential Equations and Mathematical Modelling, Analysis
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BCA Tuition
1
BCA Subject
Mathematics
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BA Tuition
2
Field tutored for
Mathematics
BA Mathematics Subjects
Algebra
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Integrals/NCERT Solutions/Exercise 7.5
Let
On solving
A = 1, B = -5, C = 4
Answered on 04/09/2019 Learn CBSE/Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.2
Let f(x)=cos(sinx),
u(x)=sinx , v(t)=cost
Where t=u(x)=sinx
Differentiating it
Since. By chain rule,
Answered on 02/09/2019 Learn CBSE/Class 12/Mathematics/Unit III: Calculus/NCERT Solutions/Exercise 2.1
Answered on 02/09/2019 Learn CBSE/Class 12/Mathematics/Unit III: Calculus/NCERT Solutions/Exercise 2.1
Let tan‾(1)=x
tan(x)=1=tan(π÷4)=π÷4,
x=π÷4;
cos¯(-1÷2)=y
cos(y)=-1÷2=cos(2π÷3)
y=2π÷3;
sin¯(-1÷2)=z⇒sin(z)=-1÷2=sin(-π÷6)
z=-π÷6;
So..........put value of x,y,z.......
π÷4+2π÷3-π÷6=9π÷12=3π÷4....
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