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Chandrakanth Class 9 Tuition trainer in Hyderabad

Chandrakanth

Engineering Tutor

Borabanda Parvathi Nagar, Hyderabad, India - 500072.

1 Student

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I can teach each and every topics very easily and make it stronger for the students.

Languages Spoken

English

Telugu

Hindi

Education

Matrusree engineering college 2017

Bachelor of Technology (B.Tech.)

Address

Borabanda Parvathi Nagar, Hyderabad, India - 500072

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Teaches

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Telugu, Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Telugu, Social Science, Mathematics, Science

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Telugu, Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Telugu, Social Science, Mathematics, Science

BTech Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

2

BTech Mechanical subjects

Internal Combustion Engines and Emissions, Finite Element Analysis, Heat & Mass Transfer, Composites: Mechanics & Processing, Mechanics of Machines, Machine Tool Technology, Operations Research, Plant Layout and Material Handling, Welding Technology, Steam & Gas Turbines, Turbomachines, Machine Design, Dynamics of Machinery, Kinematics of Machinery, Thermodynamics, Electronic Mesurement & Instrumentation, Machine Dynamics and Vibrations/ Acoustics, Metrology, Mechanical Measurements and Instrumentation, Heat Treatment of Metals and Alloys, Strength of Materials, Material Science and Metallurgy, Automotive Fuels and Fuel Sysytems, Manufacturing Technology, Fluid Mechanics, Analysis and Design of Machine Components, Refrigeration & Air Conditioning Systems, Jet Propulsion and Rocket Technology

BTech Branch

BTech Mechanical Engineering, BTech Automobile Engineering, BTech 1st Year Engineering

BTech Automobile subjects

Design Of Machine Elements, Thermodynamics, Theory Of Machines, Engineering Mechanics, Mechanics Of Machines, Strength Of Materials, Measurement And Metrology & Instrumentation

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

Yes

BTech 1st Year subjects

Basic Electronics, Advanced Mathematics (M2), Basic Mechanical Engineering, Environmental Studies, Engineering Physics, Engineering Chemistry, Engineering Mathematics (M1), Mechanics Of Solids, Engineering Graphics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

State, CBSE

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach BTech Tuition, Class 10 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Answers by Chandrakanth (6)

Answered on 09/02/2018 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

Q=mC?T Q= thermal energy or heat(J or KJ) m=mass(g or kg) C= specific heat capacity ?T=change in temperature( K or °C) Eg: specific heat of silicon is 703 J/Kg°C How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C. Solution: Q= 7 kg*( 703J/kg°c)*10&de... ...more

Q=mC?T

Q= thermal energy or heat(J or KJ)

m=mass(g or kg)

C= specific heat capacity

?T=change in temperature( K or °C)

Eg: specific heat of silicon is 703 J/Kg°C

How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C.

Solution:

Q= 7 kg*( 703J/kg°c)*10°c=49210J.

Tq.

Answers 1 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

A chemical formula of a compound is symbolic representation of its composition. A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element. For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen... ...more

A chemical formula of a compound is symbolic representation of its composition.

A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element.

For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen atoms and one sulphur atom are chemically united..

 Tq.

Answers 2 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Larger angle X Smaller angle Y We have X+Y=180..(1) larger angle exceeds thrice smaller by 20 ∴X=3Y+20..(2) Solving (1)&(2) X+Y=180 X-3Y=20 4Y=160⇒Y=40... smaller angle ∴larger angle X=140 Tq. ...more

Larger angle X

Smaller angle Y

We have X+Y=180..(1)

larger angle exceeds thrice  smaller by 20

∴X=3Y+20..(2)

Solving (1)&(2)

X+Y=180

X-3Y=20

4Y=160⇒Y=40... smaller angle

∴larger angle X=140

Tq.

 

 

Answers 8 Comments
Dislike Bookmark

Answered on 07/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

x3+ px2 +qx+2 α+β+γ=-p...(1) αβ+βγ+γα=q...(2) αγβ=-2..(3) αβ+1=0(given) From eq(3)..γ=2 2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5 =-2(α+β+2)+(-1+2β+2α)+5 ... ...more

x3+ px2 +qx+2

α+β+γ=-p...(1)

αβ+βγ+γα=q...(2)

αγβ=-2..(3)

αβ+1=0(given)

From eq(3)..γ=2

2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5

             =-2(α+β+2)+(-1+2β+2α)+5

             =0

∴2p+q+5=0.

 

Answers 2 Comments
Dislike Bookmark

Teaches

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Telugu, Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Telugu, Social Science, Mathematics, Science

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

State, CBSE

CBSE Subjects taught

Telugu, Science, Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Telugu, Social Science, Mathematics, Science

BTech Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

2

BTech Mechanical subjects

Internal Combustion Engines and Emissions, Finite Element Analysis, Heat & Mass Transfer, Composites: Mechanics & Processing, Mechanics of Machines, Machine Tool Technology, Operations Research, Plant Layout and Material Handling, Welding Technology, Steam & Gas Turbines, Turbomachines, Machine Design, Dynamics of Machinery, Kinematics of Machinery, Thermodynamics, Electronic Mesurement & Instrumentation, Machine Dynamics and Vibrations/ Acoustics, Metrology, Mechanical Measurements and Instrumentation, Heat Treatment of Metals and Alloys, Strength of Materials, Material Science and Metallurgy, Automotive Fuels and Fuel Sysytems, Manufacturing Technology, Fluid Mechanics, Analysis and Design of Machine Components, Refrigeration & Air Conditioning Systems, Jet Propulsion and Rocket Technology

BTech Branch

BTech Mechanical Engineering, BTech Automobile Engineering, BTech 1st Year Engineering

BTech Automobile subjects

Design Of Machine Elements, Thermodynamics, Theory Of Machines, Engineering Mechanics, Mechanics Of Machines, Strength Of Materials, Measurement And Metrology & Instrumentation

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

Yes

BTech 1st Year subjects

Basic Electronics, Advanced Mathematics (M2), Basic Mechanical Engineering, Environmental Studies, Engineering Physics, Engineering Chemistry, Engineering Mathematics (M1), Mechanics Of Solids, Engineering Graphics

No Reviews yet!

Answers by Chandrakanth (6)

Answered on 09/02/2018 Learn CBSE/Class 10/Science +1 Tuition/Class IX-X Tuition

Q=mC?T Q= thermal energy or heat(J or KJ) m=mass(g or kg) C= specific heat capacity ?T=change in temperature( K or °C) Eg: specific heat of silicon is 703 J/Kg°C How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C. Solution: Q= 7 kg*( 703J/kg°c)*10&de... ...more

Q=mC?T

Q= thermal energy or heat(J or KJ)

m=mass(g or kg)

C= specific heat capacity

?T=change in temperature( K or °C)

Eg: specific heat of silicon is 703 J/Kg°C

How much energy is needed to raise the temperature of a 7 kg chunk of silicon by 10°C.

Solution:

Q= 7 kg*( 703J/kg°c)*10°c=49210J.

Tq.

Answers 1 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

A chemical formula of a compound is symbolic representation of its composition. A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element. For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen... ...more

A chemical formula of a compound is symbolic representation of its composition.

A chemical formula of a compound shows its constituent elements and the number of atoms of each combining element.

For eg: The chemical formula of hydrogen sulphide if H2S.it indicates that in hydrogen sulphide two hydrogen atoms and one sulphur atom are chemically united..

 Tq.

Answers 2 Comments
Dislike Bookmark

Answered on 09/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Larger angle X Smaller angle Y We have X+Y=180..(1) larger angle exceeds thrice smaller by 20 ∴X=3Y+20..(2) Solving (1)&(2) X+Y=180 X-3Y=20 4Y=160⇒Y=40... smaller angle ∴larger angle X=140 Tq. ...more

Larger angle X

Smaller angle Y

We have X+Y=180..(1)

larger angle exceeds thrice  smaller by 20

∴X=3Y+20..(2)

Solving (1)&(2)

X+Y=180

X-3Y=20

4Y=160⇒Y=40... smaller angle

∴larger angle X=140

Tq.

 

 

Answers 8 Comments
Dislike Bookmark

Answered on 07/02/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

x3+ px2 +qx+2 α+β+γ=-p...(1) αβ+βγ+γα=q...(2) αγβ=-2..(3) αβ+1=0(given) From eq(3)..γ=2 2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5 =-2(α+β+2)+(-1+2β+2α)+5 ... ...more

x3+ px2 +qx+2

α+β+γ=-p...(1)

αβ+βγ+γα=q...(2)

αγβ=-2..(3)

αβ+1=0(given)

From eq(3)..γ=2

2p+q+5=-2(α+β+γ)+(αβ+βγ+γα)+5

             =-2(α+β+2)+(-1+2β+2α)+5

             =0

∴2p+q+5=0.

 

Answers 2 Comments
Dislike Bookmark

Contact

Load More

Chandrakanth describes himself as Engineering Tutor. He conducts classes in BTech Tuition, Class 10 Tuition and Class 9 Tuition. Chandrakanth is located in Borabanda Parvathi Nagar, Hyderabad. Chandrakanth takes at students Home and Regular Classes- at his Home. He has 2 years of teaching experience . Chandrakanth has completed Bachelor of Technology (B.Tech.) from Matrusree engineering college in 2017. HeĀ is well versed in English, Telugu and Hindi.

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