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Overview

I taught one of my student , quantitative aptitude and reasoning , for their cmat exam ,for 2 months. I have a capability to work harder and i know how to manage a student, how to deal with them and i have a good teaching skills and knowledge. I have a capability of to be a good teacher.

Languages Spoken

Hindi Mother Tongue (Native)

English Basic

Education

Govt trs college 2018

Bachelor of Science (B.Sc.)

Address

Race Course Road, Indore, India - 452001

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Teaches

Quantitative Aptitude Coaching
3 Students

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Quantitative Aptitude Coaching

1

IBPS Exam Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in IBPS Exam Coaching

1

Target section catered to

Quantitative aptitude/ Numerical ability, Reasoning Ability

Bank Clerical Exam Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Bank Clerical Exam Coaching classes

1

Target section catered to

Quantitative aptitude/ Numerical ability, Reasoning Ability

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

1

Board

CBSE, ICSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

No

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics, Physics

CBSE Subjects taught

Mathematics, Physics

Taught in School or College

No

Reviews

No Reviews yet!

FAQs

1. Which classes do you teach?

I teach Bank Clerical Exam Coaching, Class 10 Tuition, Class 12 Tuition, Class 7 Tuition, Class 8 Tuition, IBPS Exam Coaching and Quantitative Aptitude Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for 1 year.

Answers by Shivam (2)

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.2

Suppose two consecutive positive integers are x and x+1, x^2 +( x+1)^2 =365, 2 x^2+2x-364 =0, x^2+x-182=0, x^2+14x-13x-182=0, (x-13) (x+14)=0, x is a positive integer ,so only possible value of x is 13. Two consecutive positive integers are 13 and 14. ...more

Suppose two consecutive positive integers are x and x+1,

x^2 +( x+1)^2 =365,

2 x^2+2x-364 =0,

x^2+x-182=0,

x^2+14x-13x-182=0,

(x-13) (x+14)=0,

x is a positive integer ,so only possible value of x is 13.

Two consecutive positive integers are 13 and 14.

Answers 20 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

Supoose two numbers are a and b. ........(1) And ...........(2) Put the value of equation (2) in equation (1) , , , (a+10) (a-18) =0, a= -10 is not possible because cannot be negative , so a= 18 and b= 12. Therefore the larger number is 18 and the smaller number is 12. ...more

Supoose two numbers are a and b.

........(1)

And   ...........(2)

Put the value of equation (2) in equation (1) ,

,

,

(a+10) (a-18) =0,

a= -10 is not possible because  cannot be negative , so 

a= 18 and b= 12.

Therefore the larger number is 18 and the smaller number is 12.

Answers 13 Comments
Dislike Bookmark

Teaches

Quantitative Aptitude Coaching
3 Students

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Quantitative Aptitude Coaching

1

IBPS Exam Coaching

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in IBPS Exam Coaching

1

Target section catered to

Quantitative aptitude/ Numerical ability, Reasoning Ability

Bank Clerical Exam Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Bank Clerical Exam Coaching classes

1

Target section catered to

Quantitative aptitude/ Numerical ability, Reasoning Ability

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

1

Board

CBSE, ICSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

No

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics, Physics

CBSE Subjects taught

Mathematics, Physics

Taught in School or College

No

No Reviews yet!

Answers by Shivam (2)

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.2

Suppose two consecutive positive integers are x and x+1, x^2 +( x+1)^2 =365, 2 x^2+2x-364 =0, x^2+x-182=0, x^2+14x-13x-182=0, (x-13) (x+14)=0, x is a positive integer ,so only possible value of x is 13. Two consecutive positive integers are 13 and 14. ...more

Suppose two consecutive positive integers are x and x+1,

x^2 +( x+1)^2 =365,

2 x^2+2x-364 =0,

x^2+x-182=0,

x^2+14x-13x-182=0,

(x-13) (x+14)=0,

x is a positive integer ,so only possible value of x is 13.

Two consecutive positive integers are 13 and 14.

Answers 20 Comments
Dislike Bookmark

Answered on 19/06/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

Supoose two numbers are a and b. ........(1) And ...........(2) Put the value of equation (2) in equation (1) , , , (a+10) (a-18) =0, a= -10 is not possible because cannot be negative , so a= 18 and b= 12. Therefore the larger number is 18 and the smaller number is 12. ...more

Supoose two numbers are a and b.

........(1)

And   ...........(2)

Put the value of equation (2) in equation (1) ,

,

,

(a+10) (a-18) =0,

a= -10 is not possible because  cannot be negative , so 

a= 18 and b= 12.

Therefore the larger number is 18 and the smaller number is 12.

Answers 13 Comments
Dislike Bookmark

Shivam describes himself as Quantitative aptitude and logical reasoning trainer with more than 6 months of experience.. He conducts classes in Bank Clerical Exam Coaching, Class 10 Tuition and Class 12 Tuition. Shivam is located in Race Course Road, Indore. Shivam takes at students Home and Regular Classes- at his Home. He has 1 years of teaching experience . Shivam has completed Bachelor of Science (B.Sc.) from Govt trs college in 2018. HeĀ is well versed in English and Hindi.

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