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Somesh Shinde Class I-V Tuition trainer in Pune

Somesh Shinde

Sadashiv Peth, Pune, India - 411030.

1 Student

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Teaching is more than just a hobby to me. I always think that it can be done in different way. I am a student all my life and i have learn that teacher can the the way in which student think. World can be a better place with a good teacher.

Languages Spoken

Marathi Mother Tongue (Native)

Hindi Proficient

English Basic

Education

INDIAN MARITIME UNIVERSITY Pursuing

Bachelor of Technology (B.Tech.)

INDIAN MARITIME UNIVERSITY KOLKATA CAMPUS Pursuing

2nd semester

INDIAN MARITIME UNIVERSITY KOLKATA CAMPUS Pursuing

Statement of marks

Address

Sadashiv Peth, Pune, India - 411030

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Teaches

Class I-V Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Fees

₹ 225.0 per hour

Board

State, CBSE

CBSE Subjects taught

Marathi, Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Science, Marathi, Mathematics

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Mathematics, Psychology, Physics, Hindi

CBSE Subjects taught

Hindi, Physics, Philosophy, Mathematics, English

Taught in School or College

No

State Syllabus Subjects taught

Physics, Logic, Chemistry, Mathematics

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, State

CBSE Subjects taught

Physics, Chemistry, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Physics, Logic, Chemistry, Marathi, Mathematics

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

CBSE Subjects taught

Science, Marathi, Mathematics

ICSE Subjects taught

Chemistry, Hindi, Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, Hindi, Marathi

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

CBSE Subjects taught

Science, Marathi, Mathematics, Hindi

ICSE Subjects taught

Hindi, Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, Hindi, Marathi

Class 8 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE, ICSE

CBSE Subjects taught

Marathi, Hindi, Mathematics

ICSE Subjects taught

Physics, Chemistry, Marathi, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Marathi, Mathematics, Science

BCom Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

BCom Subject

Business Mathematics and Statistics

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

BTech Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

BTech Mechanical subjects

Elasticity & Plasticity, Heat & Mass Transfer, Fluid Mechanics, Strength of Materials

BTech Branch

BTech Mechanical Engineering

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

Class 6 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE, ICSE

CBSE Subjects taught

Marathi, Hindi, Mathematics

ICSE Subjects taught

Physics, Mathematics, Hindi

Taught in School or College

No

State Syllabus Subjects taught

Social science, Hindi, Marathi, Mathematics, Science

Class 7 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE, ICSE

CBSE Subjects taught

Marathi, Hindi, Mathematics

ICSE Subjects taught

Physics, Chemistry, Marathi, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Marathi, Mathematics, Science

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 1-5 do you teach for?

State and CBSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach BCom Tuition, BTech Tuition, Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and Class I-V Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for less than a year.

Answers by Somesh Shinde (3)

Answered on 09/09/2019 Learn CBSE/Class 12/Mathematics/Integrals/NCERT Solutions/Exercise 7.4

Step 1: Take 9 common from the denominator Step 2: Now make the denominater a perfect square in term of x Step 3: Now denominater may look like x^2+a^2 Step 4: now solve it
Answers 3 Comments
Dislike Bookmark

Answered on 09/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Exercise 9.5

(x-y)dy=(x+y) dx dy/dx=(x+y) /(x-y) Put y/x =t That gives dy/dx=x(dt/dx) +t Put these two values in above equation The equation become X(dt/dx) +t=(1+t) /(1-t) Solve this or I can help you further
Answers 3 Comments
Dislike Bookmark

Answered on 04/09/2019 Learn CBSE/Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.3

Steps to follow : 1st step put x= Then the denominator of bracket become the formula for cos2( ) Step 2 :invese of cos2( ) becomes sec2( ) Step 3:y=2( ) Step4 :put the value of in term of x Step 5:now you must get something like y=2cos`(x) Step 6: Differentiating this relationship with respect to... ...more

 

Steps to follow :

1st step put x= 

Then the denominator of bracket become the formula for cos2( )

Step 2 :invese of cos2( ) becomes sec2( )

Step 3:y=2( )

Step4 :put the value of  in term of x

Step 5:now you must get something like y=2cos`(x)

Step 6: Differentiating this relationship with respect to x, we obtain

 

 

Answers 2 Comments
Dislike Bookmark

Teaches

Class I-V Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Fees

₹ 225.0 per hour

Board

State, CBSE

CBSE Subjects taught

Marathi, Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Science, Marathi, Mathematics

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Mathematics, Psychology, Physics, Hindi

CBSE Subjects taught

Hindi, Physics, Philosophy, Mathematics, English

Taught in School or College

No

State Syllabus Subjects taught

Physics, Logic, Chemistry, Mathematics

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, State

CBSE Subjects taught

Physics, Chemistry, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Physics, Logic, Chemistry, Marathi, Mathematics

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

CBSE Subjects taught

Science, Marathi, Mathematics

ICSE Subjects taught

Chemistry, Hindi, Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, Hindi, Marathi

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

CBSE Subjects taught

Science, Marathi, Mathematics, Hindi

ICSE Subjects taught

Hindi, Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, Hindi, Marathi

Class 8 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE, ICSE

CBSE Subjects taught

Marathi, Hindi, Mathematics

ICSE Subjects taught

Physics, Chemistry, Marathi, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Marathi, Mathematics, Science

BCom Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

BCom Subject

Business Mathematics and Statistics

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

BTech Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

BTech Mechanical subjects

Elasticity & Plasticity, Heat & Mass Transfer, Fluid Mechanics, Strength of Materials

BTech Branch

BTech Mechanical Engineering

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

Class 6 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE, ICSE

CBSE Subjects taught

Marathi, Hindi, Mathematics

ICSE Subjects taught

Physics, Mathematics, Hindi

Taught in School or College

No

State Syllabus Subjects taught

Social science, Hindi, Marathi, Mathematics, Science

Class 7 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State, CBSE, ICSE

CBSE Subjects taught

Marathi, Hindi, Mathematics

ICSE Subjects taught

Physics, Chemistry, Marathi, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Hindi, Marathi, Mathematics, Science

No Reviews yet!

Answers by Somesh Shinde (3)

Answered on 09/09/2019 Learn CBSE/Class 12/Mathematics/Integrals/NCERT Solutions/Exercise 7.4

Step 1: Take 9 common from the denominator Step 2: Now make the denominater a perfect square in term of x Step 3: Now denominater may look like x^2+a^2 Step 4: now solve it
Answers 3 Comments
Dislike Bookmark

Answered on 09/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Exercise 9.5

(x-y)dy=(x+y) dx dy/dx=(x+y) /(x-y) Put y/x =t That gives dy/dx=x(dt/dx) +t Put these two values in above equation The equation become X(dt/dx) +t=(1+t) /(1-t) Solve this or I can help you further
Answers 3 Comments
Dislike Bookmark

Answered on 04/09/2019 Learn CBSE/Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.3

Steps to follow : 1st step put x= Then the denominator of bracket become the formula for cos2( ) Step 2 :invese of cos2( ) becomes sec2( ) Step 3:y=2( ) Step4 :put the value of in term of x Step 5:now you must get something like y=2cos`(x) Step 6: Differentiating this relationship with respect to... ...more

 

Steps to follow :

1st step put x= 

Then the denominator of bracket become the formula for cos2( )

Step 2 :invese of cos2( ) becomes sec2( )

Step 3:y=2( )

Step4 :put the value of  in term of x

Step 5:now you must get something like y=2cos`(x)

Step 6: Differentiating this relationship with respect to x, we obtain

 

 

Answers 2 Comments
Dislike Bookmark

Somesh Shinde conducts classes in BCom Tuition, BTech Tuition and Class 10 Tuition. Somesh is located in Sadashiv Peth, Pune. Somesh takes at students Home and Regular Classes- at his Home. Somesh is pursuing Bachelor of Technology (B.Tech.) from INDIAN MARITIME UNIVERSITY. HeĀ is well versed in Marathi, English and Hindi.

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