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Dharmendra Singh Class I-V Tuition trainer in Mumbai/>

Dharmendra Singh

Tutor for you

Bhayandar West, Mumbai, India - 401101.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Education

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Overview

I am very optimistic person and think positive always.
I can face and solve all problem in my life.
I have completed my Bachelor of Commerce education from Mumbai University in 2006.

Tution is my hobby and I want to prepared all children for his/ her life and I will provide practical education not only theory.

Languages Spoken

English

Hindi

Marathi

Address

Bhayandar West, Mumbai, India - 401101

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Teaches

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

3

Board

ICSE, State, CBSE

CBSE Subjects taught

Mathematics, Hindi, Marathi, English, Computers, EVS

ICSE Subjects taught

EVS, Hindi, Marathi, English, Mathematics, Science

Taught in School or College

No

State Syllabus Subjects taught

Science, English, Hindi, EVS, Mathematics, Social Science

Teaching Experience in detail in Class I-V Tuition

I’m teaching class I - V daily with good plant and basis of time table and i always teach every subject with completion of home work and by test of every chapter. I always solve every student’s all subject problems and i always give the special attention on weak students and weak subject.

Nursery-KG Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Nursery-KG Tuition

3

Subject

English, EVS, Mathematics, Drawing

Taught in School or College

No

Teaching Experience in detail in Nursery-KG Tuition

I teaching to small children for class nursery to k.g. by special attention. Small children always read with play and entertainment. I always play with small children and teach them all subject with entertainment with good manner and good habits.

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 1-5 do you teach for?

ICSE, State and CBSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class I-V Tuition and Nursery-KG Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 3 years.

Answers by Dharmendra Singh (3)

Answered on 11/07/2015 Learn Tuition/Class I-V Tuition

Here is the problem: What is the value of sin(A-b) if tan A = 9/40 and A is in the first quadrant, while cos B = -4/5 and B is in the third quadrant? I really don't get this homework. What is up with A and B? Do we need to plot the graph as well? =========================== Here's the one I just... ...more
Here is the problem: What is the value of sin(A-b) if tan A=9/40 and A is in the first quadrant, while cos B=-4/5 and B is in the third quadrant? I really don't get this homework. What is up with A and B? Do we need to plot the graph as well? =========================== Here's the one I just did with the same angles. ------------ If tan A=9/40, A is in the first quadrant, cos B=-4/5, B is in the third quadrant, find the value of cos(A+B) -------------- Find the cos(A) Tan=y/x Plot the point (40,9) --> hyp = sqrt(40^2 + 9^2) = 41 cos(A) = x/hyp = 9/41 ------------- cos(A + B) = cosA*cosB - sinA*sinB (from Wikipedia) Find sin(A) and sin(B) ------- sin(A) = y/hyp = 40/41 sin(B) = -3/5 in Q3 (it's the 3, 4, 5 triangle) -------------- cos(A + B) = cosA*cosB - sinA*sinB = (9/41)*(-4/5) - (40/41)*(-3/5) = -36/205 + 120/205 = 84/205 ============================= Use some of the values found in the previous problem: sin(A-b) = sin(A)cos(B) - cos(A)sin(B) = (40/41)*(-4/5) - (9/41)*(-3/5) = -200/205 + 27/205 = -173/205 ------------ What is up with A and B? Angles A & B are measured from the x-axis counter-clockwise. All angles on the x-y plane are measured that way. ------ Do we need to plot the graph as well? You don't have to if you don't want to. Not much to graph, just a point for each angle. For A draw a line from the Origin to (40,9) For B it's to (-3,4)
Answers 9 Comments
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Teaches

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

3

Board

ICSE, State, CBSE

CBSE Subjects taught

Mathematics, Hindi, Marathi, English, Computers, EVS

ICSE Subjects taught

EVS, Hindi, Marathi, English, Mathematics, Science

Taught in School or College

No

State Syllabus Subjects taught

Science, English, Hindi, EVS, Mathematics, Social Science

Teaching Experience in detail in Class I-V Tuition

I’m teaching class I - V daily with good plant and basis of time table and i always teach every subject with completion of home work and by test of every chapter. I always solve every student’s all subject problems and i always give the special attention on weak students and weak subject.

Nursery-KG Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Nursery-KG Tuition

3

Subject

English, EVS, Mathematics, Drawing

Taught in School or College

No

Teaching Experience in detail in Nursery-KG Tuition

I teaching to small children for class nursery to k.g. by special attention. Small children always read with play and entertainment. I always play with small children and teach them all subject with entertainment with good manner and good habits.

No Reviews yet!

Answers by Dharmendra Singh (3)

Answered on 11/07/2015 Learn Tuition/Class I-V Tuition

Here is the problem: What is the value of sin(A-b) if tan A = 9/40 and A is in the first quadrant, while cos B = -4/5 and B is in the third quadrant? I really don't get this homework. What is up with A and B? Do we need to plot the graph as well? =========================== Here's the one I just... ...more
Here is the problem: What is the value of sin(A-b) if tan A=9/40 and A is in the first quadrant, while cos B=-4/5 and B is in the third quadrant? I really don't get this homework. What is up with A and B? Do we need to plot the graph as well? =========================== Here's the one I just did with the same angles. ------------ If tan A=9/40, A is in the first quadrant, cos B=-4/5, B is in the third quadrant, find the value of cos(A+B) -------------- Find the cos(A) Tan=y/x Plot the point (40,9) --> hyp = sqrt(40^2 + 9^2) = 41 cos(A) = x/hyp = 9/41 ------------- cos(A + B) = cosA*cosB - sinA*sinB (from Wikipedia) Find sin(A) and sin(B) ------- sin(A) = y/hyp = 40/41 sin(B) = -3/5 in Q3 (it's the 3, 4, 5 triangle) -------------- cos(A + B) = cosA*cosB - sinA*sinB = (9/41)*(-4/5) - (40/41)*(-3/5) = -36/205 + 120/205 = 84/205 ============================= Use some of the values found in the previous problem: sin(A-b) = sin(A)cos(B) - cos(A)sin(B) = (40/41)*(-4/5) - (9/41)*(-3/5) = -200/205 + 27/205 = -173/205 ------------ What is up with A and B? Angles A & B are measured from the x-axis counter-clockwise. All angles on the x-y plane are measured that way. ------ Do we need to plot the graph as well? You don't have to if you don't want to. Not much to graph, just a point for each angle. For A draw a line from the Origin to (40,9) For B it's to (-3,4)
Answers 9 Comments
Dislike Bookmark

Dharmendra Singh describes himself as Tutor for you. He conducts classes in Class I-V Tuition and Nursery-KG Tuition. Dharmendra is located in Bhayandar West, Mumbai. Dharmendra takes at students Home and Regular Classes- at his Home. He has 3 years of teaching experience . He is well versed in English, Hindi and Marathi.

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