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Dr Kumar Atmjeet Class I-V Tuition trainer in Mumbai

Dr Kumar Atmjeet

Learn Science from the Scientist

Andheri West, Mumbai, India - 400053.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Scientist by profession and heart, I like to interact students from the ground level. Encourage students to think of a solution instead of just forcing mine. My style of teaching helps in developing interest in subject rather than mugging up through daily life examples. I believe no question is wierd or foolish. I rely more on concepts rather than pouring shortcuts which can be easily forgotten. I consider myself among the best when it comes to being the scientific temper in the students. Being from Scientist background and worked in cutting edge science projects, I believe my method of teaching also has to be scientific.

Languages Spoken

Hindi

English

Education

University of Delhi 2014

Doctor of Philosophy (Ph.D.)

Address

Andheri West, Mumbai, India - 400053

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Teaches

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

CBSE Subjects taught

Science, Mathematics, Sanskrit, Hindi

ICSE Subjects taught

Mathematics, Hindi, Science

Taught in School or College

No

State Syllabus Subjects taught

Science, Sanskrit, Hindi, Mathematics

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

4

Board

State, CBSE, ICSE

CBSE Subjects taught

Science, Hindi, Mathematics

ICSE Subjects taught

Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science, Hindi

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

4

Board

State, CBSE, ICSE

CBSE Subjects taught

Science, Hindi, Mathematics

ICSE Subjects taught

Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science, Hindi

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CBSE Subjects taught

Mathematics

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CBSE Subjects taught

Mathematics

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CBSE Subjects taught

Mathematics

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CBSE Subjects taught

Physics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CBSE Subjects taught

Physics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 1-5 do you teach for?

CBSE, ICSE and State

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and Class I-V Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for less than a year.

Answers by Dr Kumar Atmjeet (4)

Answered on 14/01/2018 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

Na. Since Atomic mass of Na<Fe the number of atoms for sodium will be much higher to make up 100gm. In fact ratio of no of atoms will be 56/23.
Answers 11 Comments
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Answered on 10/01/2018 Learn CBSE/Class 12/Science/Physics +1 Tuition/Class XI-XII Tuition (PUC)

In principle you will not. Because even if the wavelengths of the emitting light from the two sources are same there is no definite relationship between the phases of the two. This makes the lights passing through the two slits incoherent, which is a necessary criterion for interference.
Answers 1 Comments
Dislike Bookmark

Answered on 06/01/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Using Pythagoras’s theorem; Third side = (29^2-21^2)^(1/2)=20 Now angle B=Cos^-1 (20/21) I assume next part asks cos^2B+Sin^2B, this will be 1 irrespective of what is B Second with - sign this equals to cos 2B or 2cos^2(B)-1 Just put cos B value here and get the result. ...more

Using Pythagoras’s theorem;

Third side = (29^2-21^2)^(1/2)=20

Now angle B=Cos^-1 (20/21)

I assume next part asks cos^2B+Sin^2B, this will be 1 irrespective of what is B

Second with - sign this equals to cos 2B or 2cos^2(B)-1

Just put cos B value here and get the result.

Answers 11 Comments
Dislike Bookmark

Answered on 06/01/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

I don’t think the question is correct. The product of three roots = - Const/ coefficient of cubic term which yields -(-6)/2=3. Since product of two roots is 3 then the third one has to be 1. But 1 can’t be the root of equation. As one can easily subtitle x=1 in the equation and see it doesn’t... ...more

I don’t think the question is correct. The product of three roots = - Const/ coefficient of cubic term which yields -(-6)/2=3. 

Since product of two roots is 3 then the third one has to be 1. But 1 can’t be the root of equation. As one can easily subtitle x=1 in the equation and see it doesn’t yield 0. 

However, the question will be correct if one says that the product of two root is -3. Then answers would be -1, -2 and 3/2.

Answers 3 Comments
Dislike Bookmark

Teaches

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

CBSE Subjects taught

Science, Mathematics, Sanskrit, Hindi

ICSE Subjects taught

Mathematics, Hindi, Science

Taught in School or College

No

State Syllabus Subjects taught

Science, Sanskrit, Hindi, Mathematics

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

4

Board

State, CBSE, ICSE

CBSE Subjects taught

Science, Hindi, Mathematics

ICSE Subjects taught

Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science, Hindi

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

4

Board

State, CBSE, ICSE

CBSE Subjects taught

Science, Hindi, Mathematics

ICSE Subjects taught

Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science, Hindi

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CBSE Subjects taught

Mathematics

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CBSE Subjects taught

Mathematics

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CBSE Subjects taught

Mathematics

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CBSE Subjects taught

Physics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

CBSE Subjects taught

Physics

No Reviews yet!

Answers by Dr Kumar Atmjeet (4)

Answered on 14/01/2018 Learn CBSE/Class 9/Science +1 Tuition/Class IX-X Tuition

Na. Since Atomic mass of Na<Fe the number of atoms for sodium will be much higher to make up 100gm. In fact ratio of no of atoms will be 56/23.
Answers 11 Comments
Dislike Bookmark

Answered on 10/01/2018 Learn CBSE/Class 12/Science/Physics +1 Tuition/Class XI-XII Tuition (PUC)

In principle you will not. Because even if the wavelengths of the emitting light from the two sources are same there is no definite relationship between the phases of the two. This makes the lights passing through the two slits incoherent, which is a necessary criterion for interference.
Answers 1 Comments
Dislike Bookmark

Answered on 06/01/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Using Pythagoras’s theorem; Third side = (29^2-21^2)^(1/2)=20 Now angle B=Cos^-1 (20/21) I assume next part asks cos^2B+Sin^2B, this will be 1 irrespective of what is B Second with - sign this equals to cos 2B or 2cos^2(B)-1 Just put cos B value here and get the result. ...more

Using Pythagoras’s theorem;

Third side = (29^2-21^2)^(1/2)=20

Now angle B=Cos^-1 (20/21)

I assume next part asks cos^2B+Sin^2B, this will be 1 irrespective of what is B

Second with - sign this equals to cos 2B or 2cos^2(B)-1

Just put cos B value here and get the result.

Answers 11 Comments
Dislike Bookmark

Answered on 06/01/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

I don’t think the question is correct. The product of three roots = - Const/ coefficient of cubic term which yields -(-6)/2=3. Since product of two roots is 3 then the third one has to be 1. But 1 can’t be the root of equation. As one can easily subtitle x=1 in the equation and see it doesn’t... ...more

I don’t think the question is correct. The product of three roots = - Const/ coefficient of cubic term which yields -(-6)/2=3. 

Since product of two roots is 3 then the third one has to be 1. But 1 can’t be the root of equation. As one can easily subtitle x=1 in the equation and see it doesn’t yield 0. 

However, the question will be correct if one says that the product of two root is -3. Then answers would be -1, -2 and 3/2.

Answers 3 Comments
Dislike Bookmark

Dr Kumar Atmjeet describes himself as Learn Science from the Scientist. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Dr is located in Andheri West, Mumbai. Dr takes at students Home. He has 4 years of teaching experience . Dr has completed Doctor of Philosophy (Ph.D.) from University of Delhi in 2014. He is well versed in Hindi and English.

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