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Praveen S. Class 9 Tuition trainer in Mumbai

Praveen S.

Teacher

Kharghar, Mumbai, India - 400614.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Education

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Overview

I am very passionate about student improvement and can teach them in a nice and simple way, till he understand's the subject and grasp the basic involved behind it. Can make subject basic stronger.

Languages Spoken

Hindi Proficient

English Proficient

Education

Jabalpur 1999

Bachelor of Science (B.Sc.)

Address

Kharghar, Mumbai, India - 400614

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Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

10

Board

International Baccalaureate, IGCSE, State, CBSE, ICSE

IB Subjects taught

Physics, Mathematics, Chemistry

CBSE Subjects taught

Science, Social science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics, Hindi

IGCSE Subjects taught

Mathematics, Chemistry, Physics

Taught in School or College

Yes

State Syllabus Subjects taught

Hindi, Science, Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

10

Board

International Baccalaureate, IGCSE, State, CBSE, ICSE

IB Subjects taught

Physics, Mathematics, Chemistry

CBSE Subjects taught

Science, Social science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics, Hindi

IGCSE Subjects taught

Mathematics, Chemistry, Physics

Taught in School or College

Yes

State Syllabus Subjects taught

Hindi, Science, Mathematics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

International Baccalaureate, IGCSE, State and others

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 10 years.

Contact

Answers by Praveen S. (8)

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Factorise: (a – b)3 + (b – c)3 + (c – a)3

3(a-b+b-c+c-a)= 3*(0)=0
Answers 15 Comments
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Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

The adjacent sides of a rectangle are 16 cm and 8 cm. Find the area of the rectangle.

Area of rectangle =l*b=16*8=128 cm^2
Answers 20 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150 then what... ...more
The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150 then what will be the resulting mean?

Mean of 100 observation is 50. So by replacing value of 50 by 150 new total will be 5100 and and new mean will be 5100/100 is 51
Answers 49 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

The area of triangle ABC is 15 cm sq. If ?ABC and a parallelogram ABPD are on the same base and between... ...more
The area of triangle ABC is 15 cm sq. If ?ABC and a parallelogram ABPD are on the same base and between the same parallel lines then what is the area of parallelogram ABPD.

Area of parallelogram ABPD=2×area of ?ABC=2×15=30 sq cm since we know that AREA OF PARALLELOGRAM is twice the are of triangles if both have common base ad between same parallel lines
Answers 8 Comments
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Answered on 21/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

The lengths of the diagonals of a rhombus are 30 cm and 40 cm. Find the side of the rhombus.

For Rhombus ABCD with BD, AC as diagonals of a rhombus. We know Diagonals are bisects each other at O Now ?AOB is a right angle triangle and by Pythagoras theorem AB^2=AO^2+OB^2 Given AC=40, BD=30 ,O is midpoint of AC,BD AO=20, OB=15 AB^2=(20×20)+(15×15)=400+225=625 AB=?625=25 Therefore side of the... ...more
For Rhombus ABCD with BD, AC as diagonals of a rhombus. We know Diagonals are bisects each other at O Now ?AOB is a right angle triangle and by Pythagoras theorem AB^2=AO^2+OB^2 Given AC=40, BD=30 ,O is midpoint of AC,BD AO=20, OB=15 AB^2=(20×20)+(15×15)=400+225=625 AB=?625=25 Therefore side of the rhombus is 25cm
Answers 5 Comments
Dislike Bookmark

Contact

View All

Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

10

Board

International Baccalaureate, IGCSE, State, CBSE, ICSE

IB Subjects taught

Physics, Mathematics, Chemistry

CBSE Subjects taught

Science, Social science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics, Hindi

IGCSE Subjects taught

Mathematics, Chemistry, Physics

Taught in School or College

Yes

State Syllabus Subjects taught

Hindi, Science, Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

10

Board

International Baccalaureate, IGCSE, State, CBSE, ICSE

IB Subjects taught

Physics, Mathematics, Chemistry

CBSE Subjects taught

Science, Social science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics, Hindi

IGCSE Subjects taught

Mathematics, Chemistry, Physics

Taught in School or College

Yes

State Syllabus Subjects taught

Hindi, Science, Mathematics

No Reviews yet!

Answers by Praveen S. (8)

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Factorise: (a – b)3 + (b – c)3 + (c – a)3

3(a-b+b-c+c-a)= 3*(0)=0
Answers 15 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

The adjacent sides of a rectangle are 16 cm and 8 cm. Find the area of the rectangle.

Area of rectangle =l*b=16*8=128 cm^2
Answers 20 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150 then what... ...more
The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150 then what will be the resulting mean?

Mean of 100 observation is 50. So by replacing value of 50 by 150 new total will be 5100 and and new mean will be 5100/100 is 51
Answers 49 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

The area of triangle ABC is 15 cm sq. If ?ABC and a parallelogram ABPD are on the same base and between... ...more
The area of triangle ABC is 15 cm sq. If ?ABC and a parallelogram ABPD are on the same base and between the same parallel lines then what is the area of parallelogram ABPD.

Area of parallelogram ABPD=2×area of ?ABC=2×15=30 sq cm since we know that AREA OF PARALLELOGRAM is twice the are of triangles if both have common base ad between same parallel lines
Answers 8 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

The lengths of the diagonals of a rhombus are 30 cm and 40 cm. Find the side of the rhombus.

For Rhombus ABCD with BD, AC as diagonals of a rhombus. We know Diagonals are bisects each other at O Now ?AOB is a right angle triangle and by Pythagoras theorem AB^2=AO^2+OB^2 Given AC=40, BD=30 ,O is midpoint of AC,BD AO=20, OB=15 AB^2=(20×20)+(15×15)=400+225=625 AB=?625=25 Therefore side of the... ...more
For Rhombus ABCD with BD, AC as diagonals of a rhombus. We know Diagonals are bisects each other at O Now ?AOB is a right angle triangle and by Pythagoras theorem AB^2=AO^2+OB^2 Given AC=40, BD=30 ,O is midpoint of AC,BD AO=20, OB=15 AB^2=(20×20)+(15×15)=400+225=625 AB=?625=25 Therefore side of the rhombus is 25cm
Answers 5 Comments
Dislike Bookmark

Contact

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Praveen S. describes himself as Teacher. He conducts classes in Class 10 Tuition and Class 9 Tuition. Praveen is located in Kharghar, Mumbai. Praveen takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 10 years of teaching experience . Praveen has completed Bachelor of Science (B.Sc.) from Jabalpur in 1999. He is well versed in Hindi and English.

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