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Class 10 Tuition > Class 10 Tuition in Shikohabad > Aman Kumar Gupta

Aman Kumar Gupta Class 10 trainer in Shikohabad

Aman Kumar Gupta

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Municipal Council Rd Shikohabad, Shikohabad, India - 283135.

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Overview

Teaching is my passion and i am doing this from many years but professionally i have experience of 2 years. I am giving tuition at my and student's home. I got many prizes in different-2 activities during my schooling which enriched my understanding and knowledge as well.
During teaching i use different-2 tricks methods techniques to make student understand instead of learning. I think way of teaching matters instead of written things. Because a good mentor/guide/teacher/ is really a concerning thing.

Languages Spoken

Hindi Mother Tongue (Native)

English Basic

Education

IGNOU 2014

Bachelor of Technology (B.Tech.)

Address

Municipal Council Rd Shikohabad, Shikohabad, India - 283135

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Teaches

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Experience in School or College

I enjoy so i love teaching. I always give my best and try to use different-2 ways to make students to understand the concept instead of learning. I taught 1 year but my experience was too good. And students was happy with me.

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Experience in School or College

Teaching is my passion. I taught in different-2 ways just to make students understood the concepts. Students were satisfied with my way of teaching and this was a great experience.

Taught in School or College

Yes

Teaching Experience in detail in Class 9 Tuition

I teach in very well manner with lots of examples in different-2 ways on several topics that opens the mind of students and s/he becomes to think more about concepts. I always try to make understand in simple ways thus students can remember the topic. In this manner i enjoy when i teach as i did in the past. Students make me feel special and that is a great experience for me.

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition, Class 8 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Contact

Answers by Aman Kumar Gupta (4)

Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

The sum of the reciprocals of Rehman’s ages, (in years) 3 years ago and 5 years from now is 1/3... ...more
The sum of the reciprocals of Rehman’s ages, (in years) 3 years ago and 5 years from now is 1/3 Find his present age.

Let Rehman's present age be x So before 3 years age=(x-3) years His age after 5 years= (x+5) years So a/c to given data x(x-7)+3(x-7)=0 (x-7)(x+3)=0 So, x=7 or -3 Age can not be negative soRehman's present age is 7 years. ...more

Let Rehman's present age be x

So before 3 years age=(x-3) years

His age after 5 years= (x+5) years

So a/c to given data

 

 

 

 

x(x-7)+3(x-7)=0

(x-7)(x+3)=0

So, x=7 or -3

Age can not be negative soRehman's present age is 7 years.

 

Answers 6 Comments
Dislike Bookmark

Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

Find the roots of the following equations: ...more
Find the roots of the following equations:

1) x^2-1=3x x^2-3x-1=0 Apply quadratic formula i.e. {-b±√(b^2-4ac)}/2a So, roots= {3±√(9+4)}/2 = {3±√13}/2 So roots are {3+√13}/2 and {3-√13}/2 i.e. and 2) (x-7-x-4)×30 =11×(x+4)(x-7) -330=11×(x^2-3x-28) x^2-3x-28+30=0 X^2-3x+2=0 X^2-2x-x+2=0 x(x-2)-1(x-2)=0 (x-2)(x-1)=0 x=1,2... ...more

1) x^2-1=3x

x^2-3x-1=0

Apply quadratic formula i.e. {-b±√(b^2-4ac)}/2a

So, roots= {3±√(9+4)}/2 = {3±√13}/2  

So roots are {3+√13}/2 and {3-√13}/2  i.e. and

 

2)  (x-7-x-4)×30 =11×(x+4)(x-7)

-330=11×(x^2-3x-28)

x^2-3x-28+30=0

X^2-3x+2=0

X^2-2x-x+2=0

x(x-2)-1(x-2)=0

(x-2)(x-1)=0

x=1,2 i.e. ans

Answers 7 Comments
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Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Arithmetic Progression/NCERT Solutions/Exercise 5.3

A spiral is made up of successive semicircles, with centres alternatively at A and B, starting with centre... ...more

A spiral is made up of successive semicircles, with centres alternatively at A and B, starting with centre at A, of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm,...... as shown in the figure. What is the total length of such a spiral made of thirteen consecutive semicircles? (Take ).

[Hint: Length of the consecutive semicircles is  with centres at A, B respectively]

 

Length of semicircle=circumference/2 = 2Πr/2=Πr There are 13 semicircles with radius 0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5,6,6.5 I.e. in AP whose 1St term=0.5 & common difference=0.5 Now, total length of spiral=Π(0.5+1+1.5+2+2.5+3+3.5+4+4.5+5+5.5+6+6.5) As we know sum of an AP is= no. of terms(1St... ...more

Length of semicircle=circumference/2 = 2Πr/2=Πr

There are 13 semicircles with radius

0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5,6,6.5

I.e. in AP whose 1St term=0.5 &

common difference=0.5

Now, total length of spiral=Π(0.5+1+1.5+2+2.5+3+3.5+4+4.5+5+5.5+6+6.5)

As we know sum of an AP is=

no. of terms(1St term+last term)/2= 13(0.5+6.5)/2=13×7/2=91/2

Now put value

Total length of spiral =(22/7)×(91/2)=11×13=143cm i.e. ans

Answers 3 Comments
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Answered on 07/08/2019 Learn Tuition

Verify whether (1,-2)is a solution of 2x-3y =8 or not

 

To verify the solution of the question.just put either value of x or y then you all get another's value i.e. y or x or put value of both x and y in the equation you will get the LHS=RHS. Put x=1 2×1-3y=8 2-3y=8 2-8=3y y=(-6/3) y=-2 i.e. given so verified. Similarly when you put y=-2 you all get... ...more

To verify the solution of the question.just put either value of x or y then you all get another's value i.e. y or x or put value of both x and y in the equation you will get the LHS=RHS.

Put x=1

2×1-3y=8

2-3y=8

2-8=3y

y=(-6/3)

y=-2 i.e. given so verified.

Similarly when you put y=-2 you all get x=1.

Now, put both x=1 & y=-2

2×1-3×(-2)=8

2+6=8

8=8

LHS=RHS so verified.

Answers 294 Comments
Dislike Bookmark

Contact

Teaches

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Experience in School or College

I enjoy so i love teaching. I always give my best and try to use different-2 ways to make students to understand the concept instead of learning. I taught 1 year but my experience was too good. And students was happy with me.

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Experience in School or College

Teaching is my passion. I taught in different-2 ways just to make students understood the concepts. Students were satisfied with my way of teaching and this was a great experience.

Taught in School or College

Yes

Teaching Experience in detail in Class 9 Tuition

I teach in very well manner with lots of examples in different-2 ways on several topics that opens the mind of students and s/he becomes to think more about concepts. I always try to make understand in simple ways thus students can remember the topic. In this manner i enjoy when i teach as i did in the past. Students make me feel special and that is a great experience for me.

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

No Reviews yet!

Answers by Aman Kumar Gupta (4)

Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

The sum of the reciprocals of Rehman’s ages, (in years) 3 years ago and 5 years from now is 1/3... ...more
The sum of the reciprocals of Rehman’s ages, (in years) 3 years ago and 5 years from now is 1/3 Find his present age.

Let Rehman's present age be x So before 3 years age=(x-3) years His age after 5 years= (x+5) years So a/c to given data x(x-7)+3(x-7)=0 (x-7)(x+3)=0 So, x=7 or -3 Age can not be negative soRehman's present age is 7 years. ...more

Let Rehman's present age be x

So before 3 years age=(x-3) years

His age after 5 years= (x+5) years

So a/c to given data

 

 

 

 

x(x-7)+3(x-7)=0

(x-7)(x+3)=0

So, x=7 or -3

Age can not be negative soRehman's present age is 7 years.

 

Answers 6 Comments
Dislike Bookmark

Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Quadratic Equations/NCERT Solutions/Exercise 4.3

Find the roots of the following equations: ...more
Find the roots of the following equations:

1) x^2-1=3x x^2-3x-1=0 Apply quadratic formula i.e. {-b±√(b^2-4ac)}/2a So, roots= {3±√(9+4)}/2 = {3±√13}/2 So roots are {3+√13}/2 and {3-√13}/2 i.e. and 2) (x-7-x-4)×30 =11×(x+4)(x-7) -330=11×(x^2-3x-28) x^2-3x-28+30=0 X^2-3x+2=0 X^2-2x-x+2=0 x(x-2)-1(x-2)=0 (x-2)(x-1)=0 x=1,2... ...more

1) x^2-1=3x

x^2-3x-1=0

Apply quadratic formula i.e. {-b±√(b^2-4ac)}/2a

So, roots= {3±√(9+4)}/2 = {3±√13}/2  

So roots are {3+√13}/2 and {3-√13}/2  i.e. and

 

2)  (x-7-x-4)×30 =11×(x+4)(x-7)

-330=11×(x^2-3x-28)

x^2-3x-28+30=0

X^2-3x+2=0

X^2-2x-x+2=0

x(x-2)-1(x-2)=0

(x-2)(x-1)=0

x=1,2 i.e. ans

Answers 7 Comments
Dislike Bookmark

Answered on 09/08/2019 Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Arithmetic Progression/NCERT Solutions/Exercise 5.3

A spiral is made up of successive semicircles, with centres alternatively at A and B, starting with centre... ...more

A spiral is made up of successive semicircles, with centres alternatively at A and B, starting with centre at A, of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm,...... as shown in the figure. What is the total length of such a spiral made of thirteen consecutive semicircles? (Take ).

[Hint: Length of the consecutive semicircles is  with centres at A, B respectively]

 

Length of semicircle=circumference/2 = 2Πr/2=Πr There are 13 semicircles with radius 0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5,6,6.5 I.e. in AP whose 1St term=0.5 & common difference=0.5 Now, total length of spiral=Π(0.5+1+1.5+2+2.5+3+3.5+4+4.5+5+5.5+6+6.5) As we know sum of an AP is= no. of terms(1St... ...more

Length of semicircle=circumference/2 = 2Πr/2=Πr

There are 13 semicircles with radius

0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5,6,6.5

I.e. in AP whose 1St term=0.5 &

common difference=0.5

Now, total length of spiral=Π(0.5+1+1.5+2+2.5+3+3.5+4+4.5+5+5.5+6+6.5)

As we know sum of an AP is=

no. of terms(1St term+last term)/2= 13(0.5+6.5)/2=13×7/2=91/2

Now put value

Total length of spiral =(22/7)×(91/2)=11×13=143cm i.e. ans

Answers 3 Comments
Dislike Bookmark

Answered on 07/08/2019 Learn Tuition

Verify whether (1,-2)is a solution of 2x-3y =8 or not

 

To verify the solution of the question.just put either value of x or y then you all get another's value i.e. y or x or put value of both x and y in the equation you will get the LHS=RHS. Put x=1 2×1-3y=8 2-3y=8 2-8=3y y=(-6/3) y=-2 i.e. given so verified. Similarly when you put y=-2 you all get... ...more

To verify the solution of the question.just put either value of x or y then you all get another's value i.e. y or x or put value of both x and y in the equation you will get the LHS=RHS.

Put x=1

2×1-3y=8

2-3y=8

2-8=3y

y=(-6/3)

y=-2 i.e. given so verified.

Similarly when you put y=-2 you all get x=1.

Now, put both x=1 & y=-2

2×1-3×(-2)=8

2+6=8

8=8

LHS=RHS so verified.

Answers 294 Comments
Dislike Bookmark

Contact

Aman Kumar Gupta describes himself as Tutor. He conducts classes in Class 10 Tuition, Class 8 Tuition and Class 9 Tuition. Aman is located in Municipal Council Rd Shikohabad, Shikohabad. Aman takes at students Home and Regular Classes- at his Home. He has 2 years of teaching experience . Aman has completed Bachelor of Technology (B.Tech.) from IGNOU in 2014. He is well versed in Hindi and English.

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