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The dimensions of a certain water tank are 8m,6m and 4m. What is the pressure at the bottom of the tank l, if the tank is half filled?
P = ρ g h
Where,
P = liquid's hydrostatic pressure (in N/m2, Pa)
ρ = liquid's density (kg/m3)
Note : in case of water ρ =1000 kg/m3
g = gravitational acceleration (9.81 m/s2)
h = height of the fluid's column or depth where the pressure is measured.
Thus,
P = 1000×9.81× (8/2) = 39240 (in N/m2, Pa) or P = 39.24 KPa, KN/m2
Note : 1N/m2 = Pa
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The following formula is used to calculate the pressure on any surface :
P = ρ g h
Where,
P = liquid's hydrostatic pressure (in N/m2, Pa)
ρ = liquid's density (kg/m3)
Note : in case of water ρ =1000 kg/m3
g = gravitational acceleration (9.81 m/s2)
h = height of the fluid's column or depth where the pressure is measured.
Here i am assuming that dimensions are given in L*B*H format and hence taken height of water column to be 2 meters as tank is alf filled. Adjust accordingly if height of tank is not 4 meters.
Thus,
P = 1000×9.81× (4/2) = 19620 (in N/m2, Pa) or P = 19.62 KPa, KN/m2
Note : 1N/m2 = Pa
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