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Maharashtra board x 2020 trignometry

Venkatesan Iyer
14/03/2020 0 0

If sinα+(sinα)^2=1

Show that (cosα)^2+(cosα)^4=1

sinα+(sinα)^2=1<---- eqn 1

 

sinα=1-(sinα)^2

(sinα)^2+(cosα)^2=1 (identity)

sinα=(cosα)^2

Subsitute this in eqn 1

(cosα)^2+((cosα)^2)^2=1

(cosα)^2+(cosα)^4=1

Proved.

 

 

 

 

 

 

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