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Time of the phone call is modeled with the expoential r.v with mean 12 minutes. calculate the probability that the call will last longer than half an hour.

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Senior Statistics Teacher with 20 years of experience from University of Hyderabad

0.08208
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Qualified teacher with overall 6 years of research and teaching experience.

Formula for exponential distribution is : f(x) = me–mx By replacing the variables with mean = 12 mins and by information call will last for 0.2 hours to 0.5 hours, we can get the required probability will be : 1-me–mx So, the answer is 0.082
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Formula for exponential distribution is : f(x) = memx

By replacing the variables with mean = 12 mins and by information call will last for 0.2 hours to 0.5 hours, we can get the required probability will be : 1-memx

So, the answer is 0.082

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It Professional Trainer With 10 Years of Experience in It Industry

e^(-2.5) =0.082
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e^(-2.5) =0.082

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20 years of experience as Maths Tutor

e^(-2.5) =0.082
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Graduated from renowed Business school and expertise in teaching Mathematics and Physics

It is based on the concept of Exponential distribution. Continuous random variable as it is measured- If x is the amount of time the phone call lasts which is 30 min in this scenario As time is mean for decaying, the decaying parameter her is 1/mean = 1/12 = 0.08 So, the probability that phone call...
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It is based on the concept of Exponential distribution.

Continuous random variable as it is measured- If x is the amount of time the phone call lasts which is 30 min in this scenario

As time is mean for decaying, the decaying parameter her is 1/mean = 1/12 = 0.08

So, the probability that phone call lasts for 30 minutes is = 0.08e^-0.08*30

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Score high in Math under the my guidance with 20 years teaching experience

e^(-2.5)=0.08208
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e^(-2.5)=0.082
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enthusiastic unemployer & qualified GATE exam twice

0.082
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10 Years experience of training Xth board students for CBSE and ICSE Xth Board exams.

0.082
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Experienced Biology teacher from mumbai

e^(-2.5) =0.082
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