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A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs. 90, find the number of articles produced and the cost of each article.

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Let the number of articles be = x units Then the cost of each article = Rs (2x+3) Total cost = Rs 90 x(2x+3)=90 x(2x+15)-6(2x+15)=0 (x-6)(2x+15)=0 x=6 or x = -15/2 since x is number of articles it cannot be negative or a fraction Hence x = 6 The number of articles produced = 6 The cost...
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Let the number of articles be = x units

Then the cost of each article = Rs (2x+3)

Total cost = Rs 90

x(2x+3)=90

x(2x+15)-6(2x+15)=0

(x-6)(2x+15)=0

x=6 or  x = -15/2

since x is number of articles it cannot be negative or a fraction

Hence x = 6

The number of articles produced = 6

The cost of each article =2*6+3 = Rs 15

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Maths and Science Grade 8-10 SSC and CBSE tuitions

No of articles= 6 Cost of each article= 15 Rs
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B.Tech, M.Tech, Delhi, 15 yrs teaching experience engineering maths expert

Number of articles is 6, each cost Rs. 15/-
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