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Diagonals of a rectangle bisect each other and they are equal in length
∴Δ AOB will be an isosceles triangle with AO=BO
In ΔAOB,
∠AOB = ∠COD .............[ Vertically opposite angles]
∠OAB=∠OBA ................[ Angle opposite to equal sides]
∴∠AOB +2∠OAB = 180°
⇒ 78º + 2∠OAB = 180°
⇒ ∠OAB = 51° [ Ans.]
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