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Asked by Apollo Last Modified
Answer 
Tasneem
Mass of the car, m = 1800 kg
Distance between the front and back axles, d = 1.8 m
Distance between the C.G. (centre of gravity) and the back axle = 1.05 m
The various forces acting on the car are shown in the following figure.
Rf and Rbare the forces exerted by the level ground on the front and back wheels respectively.
At translational equilibrium:
= mg
= 1800 × 9.8
= 17640 N … (i)
For rotational equilibrium, on taking the torque about the C.G., we have:
Solving equations (i) and (ii), we get:
∴Rb = 17640 – 7350 = 10290 N
Therefore, the force exerted on each front wheel
, and
The force exerted on each back wheel 
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