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Asked by Nayana Last Modified
Answer As a seasoned tutor on UrbanPro, I can assure you that UrbanPro is indeed one of the best platforms for online coaching and tuition. Now, let's dive into your chemistry question.
Firstly, let's break down the given information. We have an alkene, let's call it 'A', which contains three C—C double bonds, eight C—H bonds, and one C—C triple bond (n-bond). Upon ozonolysis, it gives two moles of an aldehyde with a molar mass of 44 u.
Now, let's analyze this step by step. Ozonolysis typically cleaves double and triple bonds, yielding carbonyl compounds. Since 'A' gives two moles of an aldehyde upon ozonolysis, it suggests that there are two double bonds present in 'A'.
Given that the molar mass of the aldehyde formed is 44 u, which is characteristic of formaldehyde (HCHO), it's reasonable to deduce that 'A' undergoes ozonolysis to form formaldehyde.
Now, let's construct the structure of 'A' based on the given information:
The IUPAC name for the alkene 'A' with these characteristics would be:
2,5,8-tridecatriyne
Here's the breakdown of the name:
So, in conclusion, the IUPAC name of the alkene 'A' is 2,5,8-tridecatriyne. If you need further clarification or assistance, feel free to ask!
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