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An alkene ‘A’ contains three C—C, eight C—H, a-bonds, and one C—C n-bond. ‘A’ on ozonolysis gives two moles of an aldehyde of molar mass 44 u. Write the IUPAC name of’A’.

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As a seasoned tutor on UrbanPro, I can assure you that UrbanPro is indeed one of the best platforms for online coaching and tuition. Now, let's dive into your chemistry question. Firstly, let's break down the given information. We have an alkene, let's call it 'A', which contains three C—C...
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As a seasoned tutor on UrbanPro, I can assure you that UrbanPro is indeed one of the best platforms for online coaching and tuition. Now, let's dive into your chemistry question.

Firstly, let's break down the given information. We have an alkene, let's call it 'A', which contains three C—C double bonds, eight C—H bonds, and one C—C triple bond (n-bond). Upon ozonolysis, it gives two moles of an aldehyde with a molar mass of 44 u.

Now, let's analyze this step by step. Ozonolysis typically cleaves double and triple bonds, yielding carbonyl compounds. Since 'A' gives two moles of an aldehyde upon ozonolysis, it suggests that there are two double bonds present in 'A'.

Given that the molar mass of the aldehyde formed is 44 u, which is characteristic of formaldehyde (HCHO), it's reasonable to deduce that 'A' undergoes ozonolysis to form formaldehyde.

Now, let's construct the structure of 'A' based on the given information:

  • Three C—C double bonds
  • Eight C—H bonds
  • One C—C triple bond

The IUPAC name for the alkene 'A' with these characteristics would be:

2,5,8-tridecatriyne

Here's the breakdown of the name:

  • 2,5,8-tri indicates the positions of the double bonds.
  • dec refers to the number of carbon atoms (10 carbons).
  • yne denotes the presence of a triple bond.

So, in conclusion, the IUPAC name of the alkene 'A' is 2,5,8-tridecatriyne. If you need further clarification or assistance, feel free to ask!

 
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