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Asked by Akash Last Modified
Answer 
Harshit Bhardwaj
Acceleration due to gravity on the surface of moon, 
= 1.7 m s–2
Acceleration due to gravity on the surface of earth, g = 9.8 m s–2
Time period of a simple pendulum on earth, T = 3.5 s
Where,
l is the length of the pendulum
The length of the pendulum remains constant.
On moon’s surface, time period, 
Hence, the time period of the simple pendulum on the surface of moon is 8.4 s.
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