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Two wires of diameter 0.25 cm, one made of steel and the other made of brass are loaded as shown in Fig.  The unloaded length of steel wire is 1.5 m and that of brass wire is 1.0 m. Compute the elongations of the steel and the brass wires.

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Elongation of the steel wire = 1.49 × 10–4 m Elongation of the brass wire = 1.3 × 10–4 m Diameter of the wires, d = 0.25 m Hence, the radius of the wires, = 0.125 cm Length of the steel wire, L1 = 1.5 m Length of the brass wire, L2 = 1.0 m Total force exerted on the steel wire: F1...
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Elongation of the steel wire = 1.49 × 10–4 m

Elongation of the brass wire = 1.3 × 10–4 m

Diameter of the wires, d = 0.25 m

Hence, the radius of the wires,  = 0.125 cm

Length of the steel wire, L1 = 1.5 m

Length of the brass wire, L2 = 1.0 m

Total force exerted on the steel wire:

F1 = (4 + 6) g = 10 × 9.8 = 98 N

Young’s modulus for steel:

Where,

ΔL1 = Change in the length of the steel wire

A1 = Area of cross-section of the steel wire

Young’s modulus of steel, Y1 = 2.0 × 1011 Pa

Total force on the brass wire:

F2 = 6 × 9.8 = 58.8 N

Young’s modulus for brass:

Elongation of the steel wire = 1.49 × 10–4 m

Elongation of the brass wire = 1.3 × 10–4 m

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