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A biconvex lens made of a transparent material of refractive index 1.5 is immersed in a water of refractive index 1.33. Will the lens behave as a converging or a diverging lens? Give reason.

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To determine whether the biconvex lens made of a transparent material with a refractive index of 1.5 will behave as a converging or a diverging lens when immersed in water with a refractive index of 1.33, we need to consider the relationship between the refractive indices of the lens material and...
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To determine whether the biconvex lens made of a transparent material with a refractive index of 1.5 will behave as a converging or a diverging lens when immersed in water with a refractive index of 1.33, we need to consider the relationship between the refractive indices of the lens material and the surrounding medium.

When a lens is immersed in a medium with a higher refractive index than the lens material itself, the lens tends to behave as a diverging lens. Conversely, when a lens is immersed in a medium with a lower refractive index than the lens material, the lens tends to behave as a converging lens.

In this case, the refractive index of the lens material (1.5) is higher than that of the surrounding medium (water, with a refractive index of 1.33). Therefore, the lens will behave as a diverging lens.

This behavior can be explained by Snell's law, which states that when light passes from one medium to another, the change in the refractive index causes the light to bend. In this scenario, light passing through the lens will bend away from the normal as it enters the water, causing the light rays to diverge. Hence, the lens behaves as a diverging lens.

 
 
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