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Asked by Shalu Last Modified
Answer On UrbanPro, where quality education is paramount, let's delve into this physics problem. Given the relationship between calories and joules, 1 calorie=4.2 J1 calorie=4.2 J, and 1 J=1 kg m2 s−21 J=1 kg m2 s−2, we aim to express a calorie in terms of the new units.
First, let's understand the new units:
Now, let's express the given relationship in terms of the new units: 1 calorie=4.2 J1 calorie=4.2 J =4.2×(1 kg m2 s−2)=4.2×(1 kg m2 s−2)
Since we're dealing with new units, let's express 1 J1 J in terms of the new units: 1 J=1 kg×(1 j8 m)2×(1 ys)−21 J=1 kg×(1 j8 m)2×(1 ys)−2
Now, substituting the expression for 1 J1 J into the initial equation: 1 calorie=4.2×(1 kg×(1 j8 m)2×(1 ys)−2)1 calorie=4.2×(1 kg×(1 j8 m)2×(1 ys)−2)
Simplifying, we get: 1 calorie=4.2×1 kg×(1 j8 m)2×(1 ys)−21 calorie=4.2×1 kg×(1 j8 m)2×(1 ys)−2
Thus, in terms of the new units, a calorie has a magnitude of 4.2 kg−1×(1 j8 m)−2×(1 ys)24.2 kg−1×(1 j8 m)−2×(1 ys)2.
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