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Calculate the ‘spin only’ magnetic moment of M2+(aq) ion (Z = 27).
Asked by Nayana Last Modified
Answer 
Magnetic moment have formula is √n(n+2). In this question unpaired electrons is 3. So magnetic moment is √3(3+2).
Magnetic moment is √15 BM. =3.8729 BM.
Beacuse when M goes to M2+ then 2 electrons loss by 4s and 7 electrons present in 3d so M2+ have outermost configuration is 3d7 so having 3 unpaired electrons.
read lessZ = 27
17-11-08_Sonali_12_Chemistry_8_10_html_74849e29.gif){kind=small}
[Ar] 3d7 4s2
17-11-08_Sonali_12_Chemistry_8_10_html_4dd19828.gif){kind=small}
M2+ = [Ar] 3d7
3d7 = 17-11-08_Sonali_12_Chemistry_8_10_html_371fbaf8.jpg){kind=small}
i.e., 3 unpaired electrons
n = 3
17-11-08_Sonali_12_Chemistry_8_10_html_69d9ff27.gif)
μ ≈ 4 BM
read less
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