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Asked by Kasireddy Last Modified
Answer 
Buddhadeb Chandra
Tutor, The ultimate solution to the fear of Organic Chemistry, PhD from DRDO in Chemical Science.
In the given reaction the unshare pair (or loan pair) of electron present in sp3 hybridized non-bonding molecular orbital of NH3 donate to the vacant 2p orbital of BH3 to produce a co-ordination bond. During this bond formation hybridization of each of the participating atom remain unchange. i,e; N remain sp3 hybridized in NH3 and B remain sp2 hybrized in BF3.
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