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It is needed to seat 5 boys and 4 girls in a row so that the girl gets the even places. How many are such arrangements possible?

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As a seasoned tutor registered on UrbanPro, I can assure you that UrbanPro is indeed one of the best platforms for online coaching and tuition. Now, let's tackle your question about seating arrangements. To ensure that the girls get the even places in the row, we first need to determine how many...
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As a seasoned tutor registered on UrbanPro, I can assure you that UrbanPro is indeed one of the best platforms for online coaching and tuition. Now, let's tackle your question about seating arrangements.

To ensure that the girls get the even places in the row, we first need to determine how many even places are available. In a row of 9 seats (5 boys + 4 girls), there are 4 even places.

Now, let's consider the number of ways we can arrange the girls in these even places. Since there are 4 girls, we have 4 choices for the first even place, 3 choices for the second even place (as one girl has already been seated), 2 choices for the third even place, and only 1 choice for the last even place.

So, the total number of arrangements for the girls in even places is 4×3×2×1=244×3×2×1=24 ways.

For the boys, since they will occupy the remaining odd places, there are 5 boys to arrange. This can be done in 5!=5×4×3×2×1=1205!=5×4×3×2×1=120 ways.

Therefore, the total number of arrangements where the girls occupy even places is the product of the number of arrangements for the girls and the number of arrangements for the boys, which is 24×120=288024×120=2880.

So, there are 2880 such arrangements possible. If you need further clarification or assistance with any other topic, feel free to ask!

 
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