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and 
are at right angles. Asked by Riishu Last Modified
Answer 
Tasneem
Let us draw two circles of same radius which are passing through the centres of the other circle.
Here, point A and B are the centres of these circles and these circles are intersecting each other at point C and D.
In quadrilateral ADBC,
AD = AC (Radius of circle centered at A)
BC = BD (Radius of circle centered at B)
As radius of both circles are equal, therefore, AD = AC = BC = BD
Hence, 
is a rhombus and in a rhombus, the diagonals bisect each other at 90°. Hence, and are at right angles.
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