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Solution :
Join center of third circle (say X) and B
Join center of middle circle (say Y) and mid point of CD (say Q)
Then, AYQ and AXB are similar,
=> YQ/AY = BX/AX
=> YQ = 15×5/25 = 3
=> CQ = √(CY² - YQ²) = √(5² - 3²) = 4
=> CD = 8
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