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Find The Area Of Triangle DEB

Sujoy Das

06/02/2018 2 0

Question:

Solution:

CDB = 30, so DAB = 30 (alternate segment theorem)
ADB = 90
So DBE = 60 degrees.
AD = 6. sin EAD = sin 30 = DE/AD
So DE = AD/2 = 3.
So cot 60 = BE/DE..BE = 3/ root 3 = root3
So are DEB = 1/2* DE*EB = 1/2*3*root 3 = 3 root 3/2

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