UrbanPro

Take Class 9 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Search in

A racing car has a uniform acceleration of 4 m s−2. What distance will it cover in 10 s after start?

Asked by Last Modified  

5 Answers

Learn Intext Exercise 8.4

Follow 3
Answer

Please enter your answer

TEACHING EXP OF MORE THAN 8 YEARS MATHEMATICS BET RESULT IS 100

if u=0 then S= ut+1/2 at^2 s=1/2*4*100= 200m
Comments

Trained teacher, passionate about simplifying Chemistry

Given data, Initial velocity, u= 0m/s (body is starting from rest) Time, t = 10s Acceleration, a = 4ms-2 Distance covered, S, S= ut + 1/2 at2 = 0 x 10 + 1/2 ( 4x10x10) = 2x10x10 = 200m. Thus, the distance travelled is 200m
read more

Given data,

Initial velocity, u= 0m/s (body is starting from rest)

Time, t = 10s

Acceleration, a = 4ms-2

Distance covered, S,

S= ut + 1/2 at2

= 0 x 10 + 1/2 ( 4x10x10)

= 2x10x10

= 200m.

Thus, the distance travelled is 200m
read less
Comments

40m or 0.04km Speed =distance /time here distance =speed *time so, Speed =4m/s , time =10sec So distance =4*10 =40m or 40/1000km=0.04km
Comments

The stock market is a device for transferring money from the impatient to the patient

Use formula S = ut + 1/2 at2, please 2 understand as square , where S = distance covered, u = initial speed , a = acceleration and t = time S = 0 x 10 + 1/2 x 4 x 10 x 10 = 0 + 200 = 200m
Comments

Completed graduation in Mathematics from Calcutta University

200m
Comments

View 3 more Answers

Related Questions

A bus starting from rest moves with a uniform acceleration of 0.1 m s−2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.

Given- u=0 (start from rest) a= 0.1 m/s2, t= 2 min= 2x60 sec =120 sec To find- a) v=? & b) s=? Solution- a) v = u +at= 0+ 0.1x 120 = 12m/s b) s= ut + 1/2 a (t) ² = 0 + 1/2 x0. 1x (120) ²...
Poonam
0 0
5

What is the quantity which is measured by the area occupied below the velocity−time graph?

Distance The graph shows the velocity−time graph of a uniformly moving body. Let the velocity of the body at time (t) be v. Area of the shaded region = length × breath Where, Length = t Breath...
Ankita
0 0
5

What can you say about the motion of an object if its speed−time graph is a straight line parallel to the time axis?

Object is moving uniformly. A straight line parallel to the time axis in a speed−time graph indicates that with a change in time, there is no change in the speed of the object. This indicates the uniform motion of the object.
Soumya
0 0
5

What can you say about the motion of an object whose distance−time graph is a straight line parallel to the time axis?

When an object is at rest, its distance−time graph is a straight line parallel to the time axis. A straight line parallel to the x-axis in a distance−-time graph indicates that with a change...
Tushar
0 0
5

A trolley, while going down an inclined plane, has an acceleration of 2 cm s−2. What will be its velocity 3 s after the start?

In 1 sec Velocity of body increases by 2cm/sec. So in 3sec it's velocity would be 2cm/sec 3= 6cm/s
Anand
0 0
6

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Recommended Articles

With the current trend of the world going digital, electronic renaissance is a new movement that is welcomed by the new generation as it helps makes the lives of millions of people easier and convenient. Along with this rapidly changing movement and gaining popularity of Internet, e-Learning is a new tool that emerging...

Read full article >

Learning for every child starts from a very young age. While the formal methods include school curriculums and private lessons, the informal methods include dancing, music, drawing, and various fun-filling activities. Playing games and practising these types of activities helps the children get out of boredom and...

Read full article >

E-learning is not just about delivering lessons online. It has a much broader scope that goes beyond manual paper or PowerPoint Presentations. To understand the reach of E-learning and how the whole process works in developing the Educational system, we will discuss a few points here. Let us find out how this new learning...

Read full article >

While schools provide formal education to the children, the home is where they start learning about things informally. Parents think that schools will take the initiative to educate their children. Well, this is partially true, as parents also play an essential role in bringing up their child. For the development of particular...

Read full article >

Looking for Class 9 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 9 Tuition Classes?

The best tutors for Class 9 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 9 Tuition with the Best Tutors

The best Tutors for Class 9 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more