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Total distance covered = x km
Fare for 1st kilometre = Rs 8
Fare for the rest of the distance = Rs (x − 1) 5
Total fare = Rs [8 + (x − 1) 5]
y = 8 + 5x − 5
y = 5x + 3
5x − y + 3 = 0
It can be observed that point (0, 3) and satisfies the above equation. Therefore, these are the solutions of this equation.
x | 0 | |
y | 3 | 0 |
The graph of this equation is represented as follows:
It can be noticed that variable x and y are representing the distance covered and the fare paid for that distance respectively. These quantities may not be negative. Hence, only those values of x and y lying in the 1st quadrant will be considered.
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