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If HCF (6, a) = 2 and LCM (6, a) = 60, then find a.

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60 * 2 = 6 * a a= 10
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Maths and English teacher for 6th to 8th Class (CBSE & ICSE). Done B.Ed in Maths and B.Tech in ECE

HCF*LCM/FIRST NO= SECOND NO = 2*60/6 = 20.
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26. If H.C.F. (6, x) = 2 and L.C.M. (6, x) = 60, find x.
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h.cf*lcm/first no.=second no. 2*60/6=20.
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20.
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20.
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a=20
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Mathematician

20
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HCF*LCM=6*a 2*60=6*a (2*60)/6=a =20
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