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Asked by Shreyas Last Modified
Answer 
Let mass of the ball = m kg
Initial height ,h1= 12 metre
Final height , h2= 9 metre
Initial P.E = mgh1
= m × 9.8 × 12
Final P.E = m × g × h2
= m × 9.8 × 9
(Final P.E/ Initial P.E) ={ (m ×9.8 ×9) /(m ×9.8×12) }
=3/4
Final P.E =[ 3 × Initial P.E] / 4
Loss in P.E is 1/4 of initial P.E
% loss = (1/4)×100 = 25
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