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Asked by Vinay Last Modified
Answer 
The objects move together after the collision and have a common velocity. So it's a perfectly inelastic collision.
To find the velocity we use Law of conservation of linear momentum.
Given velocity v1= 36kmph = 36*5/18 = 10m/s
M1v1 + m2 v2 = (m1+m2)v
9000*10 + 0 = (9000+9000)v
V = 5m/s
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Use conservation Law of linear momentum ,
Pi = Pf
Pi = initial momentum = mV
Pf = final momentum = ( m + m) V1
so, mV = ( m + m )V1
V1 = V/2 = 36/2 = 18 km/h
speed after collision = 18 km/h
this is an example of enelastic collision in this collision , energy not conserved , e
g loss
It is perfectly in elastic collision .by momentum conservation theorem we can find out final velocity .
Using Principle of Conservation of Momentum, P1=P2, ie, M1V1=M2V2
=> (9000+0)*36 = (9000+9000)*V2
=> 18 = V2
Therefore, Velocity of joint carriage after the collision is 18 kmph.
The objects move together after the collision and have a common velocity. So it's a perfectly inelastic collision.
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