Osmania University, Hyderabad, India - 500007.
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Telugu Mother Tongue (Native)
Hindi Basic
English Basic
Chaitanya Bharathi Institute of Technology Pursuing
Bachelor of Engineering (B.E.)
Osmania University Pursuing
Masters of Engineering
Government Polytechnic Masab Tank 2018
Diploma in Civil Engineering
Osmania University, Hyderabad, India - 500007
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Engineering Diploma Branch
Civil Engineering Diploma, Engineering Diploma 1st Year
Engineering Diploma Subject
Workshop Drawing, Basic Physics, Basic Math, Engineering Mathematics, Communication Skills, English, Engineering Mechanics
Civil Engineering Diploma Subject
Applied Mathematics (CE and ME Group), Transportation Engineering, Hydraulics, Computer Aided Drawing, Theory Of Structures, Water shade Management, Design Of Steel Structures, Building Drawing, Concrete Technology, Irrigation Engineering, Estimating & Costing, Design of Structures, Architectural Practices and Interior Design, Highway Engineering, Building Construction, Surveying, Geo Technical Engineering, Micro Irrigation, Mechanics of Structures, Environment Engineering
Type of class
Regular Classes, Crash Course
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
1. Which Engineering Diploma branches do you tutor for?
Civil Engineering Diploma and Engineering Diploma 1st Year
2. Do you have any prior teaching experience?
No
3. Which classes do you teach?
I teach Engineering Diploma Tuition Class.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for less than a year.
Answered on 13/05/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic
Given ratio of present ages P and Q ages is 5:7
Therefore, P = 5x and Q = 7x
Difference of Q present = 7x and
P's age after 6years = 5x+6
is 2
i.e. |7x-5x-6| = 2
=(2x-6) = 2
= 2x-6 =+2, -2
From above eqn x = 4 or x = 2
Sum of present ages of P and Q when x = 4 is 48
Sun of present ages of P and Q when x = 2 is 24
Check :
When x = 4
P = 20 , Q = 28. Sum is 48
Difference is 28-(20+6) = 2 ( hence checked)
When
x = 2
P = 10 and Q = 14.Sum is 24
Difference is (10+6) - 14 = 2 ( Hence checked)
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Engineering Diploma Branch
Civil Engineering Diploma, Engineering Diploma 1st Year
Engineering Diploma Subject
Workshop Drawing, Basic Physics, Basic Math, Engineering Mathematics, Communication Skills, English, Engineering Mechanics
Civil Engineering Diploma Subject
Applied Mathematics (CE and ME Group), Transportation Engineering, Hydraulics, Computer Aided Drawing, Theory Of Structures, Water shade Management, Design Of Steel Structures, Building Drawing, Concrete Technology, Irrigation Engineering, Estimating & Costing, Design of Structures, Architectural Practices and Interior Design, Highway Engineering, Building Construction, Surveying, Geo Technical Engineering, Micro Irrigation, Mechanics of Structures, Environment Engineering
Type of class
Regular Classes, Crash Course
Class strength catered to
Group Classes, One on one/ Private Tutions
Taught in School or College
No
Answered on 13/05/2022 Learn CBSE/Class 2/Maths/Mental Arithmetic
Given ratio of present ages P and Q ages is 5:7
Therefore, P = 5x and Q = 7x
Difference of Q present = 7x and
P's age after 6years = 5x+6
is 2
i.e. |7x-5x-6| = 2
=(2x-6) = 2
= 2x-6 =+2, -2
From above eqn x = 4 or x = 2
Sum of present ages of P and Q when x = 4 is 48
Sun of present ages of P and Q when x = 2 is 24
Check :
When x = 4
P = 20 , Q = 28. Sum is 48
Difference is 28-(20+6) = 2 ( hence checked)
When
x = 2
P = 10 and Q = 14.Sum is 24
Difference is (10+6) - 14 = 2 ( Hence checked)
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Miyapur, Hyderabad 
