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Overview

Hello this is tanya... Basically i m student but as i love teaching i m here i give home tution as well as online too... I m currently in 3rd year of bsc... And i know studies can be fun if done in a good way..

Languages Spoken

Hindi Proficient

English Proficient

Education

St Aloysius college Pursuing

Bachelor of Science (B.Sc.)

Address

Bilhari, Jabalpur, India - 482020

Verified Info

Phone Verified

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Teaches

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

2

Board

State, ICSE, CBSE

CBSE Subjects taught

Hindi, EVS, Science, Mathematics, English, Sanskrit, Social Science

ICSE Subjects taught

English, Social Studies, Hindi, EVS, Sanskrit, Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

English, Sanskrit, Social Science, Science, Mathematics, Hindi, EVS

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

ICSE, CBSE, State

CBSE Subjects taught

Hindi, English, Mathematics, Social science, Science, Sanskrit

ICSE Subjects taught

EVS, Hindi, Home Science, History and Civics, Biology, English, Chemistry, Mathematics, Geography, Sanskrit, English Literature

Experience in School or College

Its was just awesome while teaching i not only teach i get to know a lot i learn alot and just my students are my friends

Taught in School or College

Yes

State Syllabus Subjects taught

English, Sanskrit, Social Science, Science, EVS, Mathematics, Hindi

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

History, Hindi, Geography, Chemistry, Biology, English, Mathematics, English Literature, EVS

CBSE Subjects taught

English, Hindi, Chemistry, History, Mathematics, Biology, Geography, Home Science

Taught in School or College

No

State Syllabus Subjects taught

English, Sanskrit, Hindi, Chemistry, History, Geography, Biology, Home Science

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 1-5 do you teach for?

State, ICSE and CBSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition and Class I-V Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Contact

Answers by Tanya S. (1)

Answered on 29/06/2020 Learn CBSE/Class 11

How you will evaluate ∫logxdx.

We need ∫logxdx∫log⁡xdx It can be done by using integration by parts, i.e., ∫udv=uv−∫vdu∫udv=uv−∫vdu By ILATE, log function should have more priority than algebraic function, So, u=logx,u=log⁡x, dv=dx⇒v=xdv=dx⇒v=x So, ∫logxdx=logx.(x)−∫x.(logx)′∫log⁡xdx=log⁡x.(x)−∫x.(log⁡x)′ ⇒xlogx−∫x.1xdx⇒xlog⁡x−∫x.1xdx ⇒xlogx−∫dx⇒xlog⁡x−∫dx ⇒xlogx−x+C⇒xlog⁡x−x+C ∴∫logxdx=xlogx−x+C∴∫log⁡xdx=xlog⁡x−x+C Where... ...more

We need ∫logxdx∫log⁡xdx

It can be done by using integration by parts,

i.e., ∫udv=uv−∫vdu∫udv=uv−∫vdu

By ILATE, log function should have more priority than algebraic function,

So, u=logx,u=log⁡x,

dv=dx⇒v=xdv=dx⇒v=x

So, ∫logxdx=logx.(x)−∫x.(logx)′∫log⁡xdx=log⁡x.(x)−∫x.(log⁡x)′

⇒xlogx−∫x.1xdx⇒xlog⁡x−∫x.1xdx

⇒xlogx−∫dx⇒xlog⁡x−∫dx

⇒xlogx−x+C⇒xlog⁡x−x+C

∴∫logxdx=xlogx−x+C∴∫log⁡xdx=xlog⁡x−x+C

Where C is the integration constant.

Answers 218 Comments
Dislike Bookmark

Contact

Teaches

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

2

Board

State, ICSE, CBSE

CBSE Subjects taught

Hindi, EVS, Science, Mathematics, English, Sanskrit, Social Science

ICSE Subjects taught

English, Social Studies, Hindi, EVS, Sanskrit, Science, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

English, Sanskrit, Social Science, Science, Mathematics, Hindi, EVS

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

ICSE, CBSE, State

CBSE Subjects taught

Hindi, English, Mathematics, Social science, Science, Sanskrit

ICSE Subjects taught

EVS, Hindi, Home Science, History and Civics, Biology, English, Chemistry, Mathematics, Geography, Sanskrit, English Literature

Experience in School or College

Its was just awesome while teaching i not only teach i get to know a lot i learn alot and just my students are my friends

Taught in School or College

Yes

State Syllabus Subjects taught

English, Sanskrit, Social Science, Science, EVS, Mathematics, Hindi

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

History, Hindi, Geography, Chemistry, Biology, English, Mathematics, English Literature, EVS

CBSE Subjects taught

English, Hindi, Chemistry, History, Mathematics, Biology, Geography, Home Science

Taught in School or College

No

State Syllabus Subjects taught

English, Sanskrit, Hindi, Chemistry, History, Geography, Biology, Home Science

No Reviews yet!

Answers by Tanya S. (1)

Answered on 29/06/2020 Learn CBSE/Class 11

How you will evaluate ∫logxdx.

We need ∫logxdx∫log⁡xdx It can be done by using integration by parts, i.e., ∫udv=uv−∫vdu∫udv=uv−∫vdu By ILATE, log function should have more priority than algebraic function, So, u=logx,u=log⁡x, dv=dx⇒v=xdv=dx⇒v=x So, ∫logxdx=logx.(x)−∫x.(logx)′∫log⁡xdx=log⁡x.(x)−∫x.(log⁡x)′ ⇒xlogx−∫x.1xdx⇒xlog⁡x−∫x.1xdx ⇒xlogx−∫dx⇒xlog⁡x−∫dx ⇒xlogx−x+C⇒xlog⁡x−x+C ∴∫logxdx=xlogx−x+C∴∫log⁡xdx=xlog⁡x−x+C Where... ...more

We need ∫logxdx∫log⁡xdx

It can be done by using integration by parts,

i.e., ∫udv=uv−∫vdu∫udv=uv−∫vdu

By ILATE, log function should have more priority than algebraic function,

So, u=logx,u=log⁡x,

dv=dx⇒v=xdv=dx⇒v=x

So, ∫logxdx=logx.(x)−∫x.(logx)′∫log⁡xdx=log⁡x.(x)−∫x.(log⁡x)′

⇒xlogx−∫x.1xdx⇒xlog⁡x−∫x.1xdx

⇒xlogx−∫dx⇒xlog⁡x−∫dx

⇒xlogx−x+C⇒xlog⁡x−x+C

∴∫logxdx=xlogx−x+C∴∫log⁡xdx=xlog⁡x−x+C

Where C is the integration constant.

Answers 218 Comments
Dislike Bookmark

Contact

Tanya S. conducts classes in Class 10 Tuition, Class 11 Tuition and Class I-V Tuition. Tanya is located in Bilhari, Jabalpur. Tanya takes at students Home, Regular Classes- at her Home and Online Classes- via online medium. She has 2 years of teaching experience . Tanya is pursuing Bachelor of Science (B.Sc.) from St Aloysius college . She is well versed in Hindi and English.

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