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Lesson Posted on 24/02/2018 Learn BTech Information Science Engineering
Infix Expression To Post-fix Expression Conversion Procedure
SR-IT Academy
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Algorithm
1. Scan the infix expression from left to right.
2. If the scanned character is an operand, output it.
3. Else,
a. If the precedence of the scanned operator is greater than the precedence of the operator in the stack (or the stack is empty), push it.
b. Else, Pop the operator from the stack until the precedence of the scanned operator is less-equal to the precedence of the operator residing on the top of the stack. Push the scanned operator to the stack.
4. If the scanned character is an ‘(‘, push it to the stack.
5. If the scanned character is an ‘)’, pop and output from the stack until an ‘(‘is encountered.
6. Repeat steps 2-6 until infix expression is scanned.
7. Pop and output from the stack until it is not empty.
read lessLesson Posted on 03/01/2018 Learn BTech Information Science Engineering
Debraj Paul
I had completed MSc in Maths I am an experienced, qualified icse board school teacher with over 12+...
Lesson Posted on 05/07/2017 Learn BTech Information Science Engineering
Shiladitya Munshi
Well, I love spending time with students and to transfer whatever computing knowledge I have acquired...
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Lesson Posted on 05/07/2017 Learn BTech Information Science Engineering
What Is The Difference Between Scope And Lifetime?
Shiladitya Munshi
Well, I love spending time with students and to transfer whatever computing knowledge I have acquired...
Lesson Posted on 05/07/2017 Learn BTech Information Science Engineering
Understanding Big Omega (?), Big Theta (?), Small Oh (o) And Small Omega (?) Notations
Shiladitya Munshi
Well, I love spending time with students and to transfer whatever computing knowledge I have acquired...
f(x) = Ω(g(x))
(big-omega) means that the growth rate of f(x)
is asymptotically greater than or equal to the growth rate of g(x)
f(x) = Θ(g(x))
(big - theta) means that the growth rate of f(x)
is asymptotically equal to the growth rate of g(x)
b) 0<= C1*g(n) <= f(n) <= C2*g(n) for any value of n => C3
What are Small Oh and Small Omega?
f(x) = o(g(x)) (small-oh) means that the growth rate of f(x) is asymptotically less than to the growth rate of g(x).
On the other hand, f(x) = ω(g(x))
(small-omega) means that the growth rate of f(x)
is asymptotically greater than the growth rate of g(x).
b) 0<= C1*g(n) < f(n) for any value of n => C2
So this gives a loose lower bound for complexities of f(x).
Lesson Posted on 05/07/2017 Learn BTech Information Science Engineering
A Tutorial On Dynamic Programming
Shiladitya Munshi
Well, I love spending time with students and to transfer whatever computing knowledge I have acquired...
What is Dynamic Programming?
Dynamic Programming, DP in short, is an intelligent way of solving a special type of complex problems which otherwise would hardly be solved in realistic time frame.
What is that special type of problems?
DP is not best fit for all types of complex problems, it is well suited for the problems with following characteristics only:
Wait. Don't jump into any conclusion right now. We have not studied the DP procedures yet! we are currently studying the nature of DP problems only. So it will be too early to compare Divide and Conquer with DP.
But this is true, that just a mere look at the characteristics of DP problems gives a feeling that DP is close to Divide and Conquer. But there is a MAJOR difference, in Divide and Conquer, at any stage, the sub problems enjoy No Inter-Dependencies.
Let us put this on hold. We will revert back to this topic once more only after we have got some experience in DP. But for the time being, take it from me that DP and Divide & Conquer are not same.
Why do not you say how DP works?
DP works as simple as possible. After the problem is broken down to trivial sub-problems in levels, DP starts solving the sub problems bottom up. Once a sub problem is solved, solution is written down (saved) into a table so that if the same sub problem reappears, we get a ready made solution. This is done in every level.
What is so special about this process?
Yes. It is special. See while you decompose a problems into sub problems, sub problems into sub sub problems and so on, you ultimately reach to a point when you need to solve the same sub problems many a times. And this "many" is not a child's play in real life. Lots of computational resources are unnecessarily spent on this which makes the process sluggish with poor time complexity values.
With DP you can avoid the re computations of the same sub problems.This will save a lot of time and other computational resources. But there are table look ups for solving reappearing sub problems, and this is not going to offer a bed of roses. This will surely take some time, but with hashing and some other smart alternatives, table look ups can be made easy.
Getting out of my head! Show me how DP works with an example.
Lets think of Fibonacci series. We know that Fib(n) = Fib(n-1) + Fib(n-2). Hence to compute Fib(4),
Fib(4) = Fib(3) + Fib(2)
= (Fib(2) + Fib(1)) + Fib(2)
= ((Fib(1) + Fib(0)) + Fib(1)) + Fib(2)
= ((Fib(1) + Fib(0)) + Fib(1)) + (Fib(1) + Fib(0))
This could easily be done with Divide and Conquer with recursion. But there will be several call for the trivial case Fib(1) and Fib(0).
But in DP style we can think that
Fib(4) ------------------- level 0
Fib(3) + Fib(2) ------------------ level 1
Fib(2) + Fib(1)-------------------------- level 2
Fib(1) + Fib(0) -------------------------------- level 3
There will be only two calls of Fib(1) and Fib(0) altogether (shown in violet at level 3). The second Fib(1) (shown in red at level 2) will not be called at all as the result of that is already with us. Similarly Fib(2) (shown in green at level 1) will not be called at all as it has already been computed at level 2. In this way we could avoid re-computations in two occasions.
This is the strength of DP. This strength seems trivial with this trivial example, but as the problem size will grow, this strength will seem to have prominent advantage. Just Think of fib(100)
Is Dynamic Programming a process to find solution quicker?
Yes it is, but the nature of the solution we are talking to is an optimal solution not the exact one. The principle of optimality applies if the optimal solution to a problem always contains optimal solutions to all subproblems . Take the following example:
Let us consider the problem of making N Rupees with the fewest number of Rupee coins.
Either there is a coin of value N Rupees (Exact Solution), or the set of coins making up an optimal solution for N Rupees can be divided into two nonempty subsets, n1 Rupees and n2 Rupees (Optimal Solution).
If any of the n1 Rupees or n2 Rupees, can be made with fewer number of coins, then clearly N can be made with fewer coins, hence solution was not optimal.
Tell me more on Principle of Optimality:
The principle of optimality holds if
Every optimal solution to a problem contains optimal solutions to all subproblems
The principle of optimality does not say
If you have optimal solutions to all subproblems then you can combine them to get an optimal solution
Example: If we have infinite numbers of coins of 1cents, 5 cents, 10 cents only then optimal solution to make 7 cents is 5 cents + 1 cent + 1 cent, and the optimal solution to make 6 cents is 5 cents + 1 cent, but the optimal solution to make 13 cent is NOT 5 cents + 1 cent + 1 cent + 5 cents + 1 cent
But there is a way of dividing up 13 cents into subsets with optimal solutions (say, 11 cents + 2 cents) that will give an optimal solution for 13 cents. Hence, the principle of optimality holds for this problem.
Let us see one example where Principle of Optimality does not hold.
In the following graph
The longest simple path (path not containing a cycle) from A to D is A->B->C->D. However, the sub path A->B is not the longest simple path from A to B (A->C->B is longer)
The principle of optimality is not satisfied for this problem. Hence, the longest simple path problem cannot be solved by a dynamic programming approach.
Can you give me a thorough example of DP?
Why not! Following is an example of working of Dynamic Programming. It presents a comparative analysis of working of DP with the working of Divide & Conquer.
Let us consider the Coin Counting Problem. It is to find the minimum number of coins to make any amount, given a set of coins.
If we are given with a set of coin of 1 unit, 10 units and 25 units, then to make 31, how many minimum numbers of coins are required?
Let us check whether the greedy method will work or not. Greedy Method says that just choose the largest coin that does not overshoot the desired amount. So at the first step, we will take one coin of 25 units and then successively in each of next six steps, we will take one 1 unit coin. So ultimately the solution of Greedy Method is 31 = 25 + 1 + 1 + 1 + 1 + 1 + 1 (Total 7 nk!umbers of coins needed)
But evidently there is better solution like 31 = 10 + 10 + 10 + 1 (only 4 numbers of coins are needed).
Hence Greedy Method will never work.
Now let us check whether any better algorithm exists or not! What about the following?
To make K units:
If there is a K unit coin, then that one coin is the minimum
Otherwise, for each value i < K,
Find the minimum number of coins needed to make i units
Find the minimum number of coins needed to make K - i units
Choose the value of i that minimizes this sum
Yes. This will work. This is actually following Divide & Conquer Principle but there are two problems with this. This solution is very recursive and it requires exponential amount of work to be done.
Now, if we fix the given set of coins as 1, 5, 10, 21, 25 and if the desired amount is 63, then the previous solution will require solving 62 recursive sub problems.
What If we think to choose the best solution among?
In this case, we need to solve only 5 recursive sub problems. So obviously, this second solution is better than the first solution. But still, this second solution is also very expensive.
Now let us check how DP can solve it!
To make it shorter in length, let us think that desired value is 13 units and the set of coin given is 1 unit, 3 units, and 4 units.
DP solves first for one unit, then two units, then three units, etc., up to the desired amount and saves each answer in a table (Memoization). Hence it goes like
For each new amount N, compute all the possible pairs of previous answers which sum to N
For example, to find the solution for 13 units,
First, solve for all of 1 unit, 2 units, 3 units, ..., 12 units
Next, choose the best solution among:
This will run like following:
There’s only one way to make 1unit (one coin)
To make 2 units, try 1 unit +1 unit (one coin + one coin = 2 coins)
To make 3 units, just use the 3 units coin (one coin)
To make 4 units, just use the 4 units coin (one coin)
To make 5 units, try
To make 6 units, try
Etc.
Ok. I got it but how could you say that computationally this is the best?
The first algorithm is recursive, with a branching factor of up to 62. Possibly the average branching factor is somewhere around half of that (31). So the algorithm takes exponential time, with a large base.
The second algorithm is much better—it has a branching factor of 5. Still this is exponential time, with base 5.
The dynamic programming algorithm is O(N*K), where N is the desired amount and K is the number of different kinds of coins.
So I don’t hesitate to say that computationally, DP algorithm works best among these threes.
What is this Matrix Chain Multiplication Problem?
Suppose we have a sequence or chain A1, A2, …, An of n matrices to be multiplied. That is, we want to compute the product A1A2…An. Now there are many possible ways (parenthesizations) to compute the product.
Let us consider the chain A1, A2, A3, A4 of 4 matrices. Now to compute the product A1A2A3A4,there are 5 possible ways as described below:
(A1(A2(A3A4))), (A1((A2A3)A4)), ((A1A2)(A3A4)), ((A1(A2A3))A4), (((A1A2)A3)A4)
Each of these options may lead to the different number of scalar multiplications, and we have to select the best one (option resulting fewer number of Scalar Multiplications)
Hence the problem statement looks something like: “Parenthesize the product A1A2…An such that the total number of scalar multiplications is minimized”
Please remember that the objective of Matrix Chain Multiplication is not to do the multiplication physically, rather the objective is to fix the way of that multiplication ordering so that the number of scalar multiplication gets minimized.
Give me one real example:
Ok. But before I show you one real example, let us revisit the algorithm which multiplies two matrices. It goes like following:
Input: Matrices Ap×q and Bq×r (with dimensions p×q and q×r)
Result: Matrix Cp×r resulting from the product A·B
MATRIX-MULTIPLY(Ap×q , Bq×r)
In the above algorithm, scalar multiplication in line 5 dominates time to compute C Number of scalar multiplications read less
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Lesson Posted on 05/07/2017 Learn BTech Information Science Engineering
Do You Give Enough Importance In Writing Main () In C Language?
Shiladitya Munshi
Well, I love spending time with students and to transfer whatever computing knowledge I have acquired...
I am sure; you guys are quite familiar with C programming, especially, while it comes to write the first line of your main function. In my class, I have seen many of my students are writing main function with many different forms.
Some portion of students write like main(), some write main(void), again some of the students write void main(void) and int main(void). Now the question is which one is right?
All are right. Generally you write your C programs with Turbo C editor, or with any other, and generally they do not complain if you write any of them. But still, there is a factor of theoretical perfection. Trivial programming exercises may not be affected with whatever way you follow to declare main function, but in critical cases, your decision may make differences. This is why you should know which one is theoretically perfect.
As we always know that main is a function which gets called at the beginning of execution of any program. So like other functions, main must have a return type and it must expect arguments. If you are not calling your program (or your main likewise) from the command prompt, your mainfunction should not bother for any arguments, so actually you should call your main with void argument, like main(void).
Now you may raise a point that main() itself suggest that no arguments are passed, so what is wrong with it? See one thing, in your current compiler, the default argument is void, but the same may not be true with other compilers or platforms. So you may end up with portability issues! Keep in mind, A Good Programmer Never Rely On Defaults. So please don’t rely on default things any more, clearly write that your main function is not expecting any arguments by writing main(void).
You already have an idea that a function can never work unless and until it is being called by any other program component. This is true for main also. The function main must be called by someone! Who is that? Who calls main function? It is the operating system who calls main function. Now the thing is, your operating system may decide to do any other job according to the success or failure of running your main function. It may so happen that if your program runs successfully, operating system will call a program P1, and if your program does not work, your operating system will call another program P2. So what if your operating system has no idea that your program did run actually or not? There lies the importance of return type of main. Your main function should return something to your operating system back to indicate whether it has ran successfully or not. The rule is if operating system gets an integer 0 back, it takes as main has ran successfully and any non zero value indicates the opposite. So your main program should return an integer. Hence you should write int main(void). Just to add with this, don’t forget to return 0 at the end of your main program so that, if all of your codes run successfully, your main function is capable of returning 0 to the operating system back, indicating that it was a success.
In this point you may argue, that your programs runs quite well even if you do not provide return type to main and you just write main(void). How come it is possible?
Once again, at your age, you are writing just some of trivial academic codes. The situations here are not such critical that your operating system may decide any other thing depending on the success or failure of your main(). But, in near future, you are to write such critical programs, so get prepared from now.
Cool, so to conclude, int main(void) is perfect to write and I encourage you to write like that along with a return 0 at the last line.
read lessLesson Posted on 05/07/2017 Learn BTech Information Science Engineering
Shiladitya Munshi
Well, I love spending time with students and to transfer whatever computing knowledge I have acquired...
Are reference and pointers same?
No.
I have seen this confusion crumbling up among the student from the first day. So better clear out this confusion at thevery beginning.
Pointers and reference both hold the address of other variables. Up to this they look similar, but their syntax and further consequences are totally different. Just consider the following pieces of code
Code 1 Code 2
int i; int i;
int *p = &i; int &r = i ;
Here in code 1 we have declared and defined one integer pointer p which points to variable i, that is now , p holds the address of i.
In code 2, we have declared and defined one integer reference r which points to variable i, that is now, r holds the address of i. This is completely same as that of p.
So where is the difference?
The first difference can be found just by looking at the code. Their syntaxes!
Secondly the difference will come up when they would be used differently to assign a value (suppose 10) to i.
If you are using a pointer, you can do it like *p = 10; but if you are using a reference, you can do it like r = 10. Just be careful to understand that when you are using pointers, the address must be dereferenced using the *, whereas, when you are using references, the address is dereferenced without using any operators at all.
This notion leaves a huge effect as consequences. As the address of the variable is dereferenced by * operator, while using a pointer, you are free to do any arithmetic operations on it. That is you can increment the pointer p to point to the next address just by doing p++. But, this is not possible using references. So a pointer can point to many different elements during its lifetime; where as a reference can refer to only one element during its life time.
Does C language support references?
No. The concept of reference has been added to C++, not in C. So if you run the following code, C compiler will object then and there.
#include
#include
int main(void)
{
int i;
int &r = i;
r = 10;
printf("\n Value of i assigned with reference r = %d",i);
getch();
return 0;
}
But if you are using any C++ compiler, this code will work fine as expected.
If there is no concept of reference in C language, then how come there exists C function call by reference?
Strictly speaking, there is no concept of function call by reference in C language. C only supports function call by value. Though in some books ( I will not name any one) it is written that C supports function call by reference or the simulation of function call by reference can be achieved through pointers, I will strongly say that C language neither directly supports function call by reference, nor provides any other mechanism to simulate the same effect.
I know you are at your toes to argue that what about calling a C function with address of a variable and receiving it with a pointer? The change made to that variable within the function has a global effect. How this cannot be treated as an example of function call by reference?
You probably argue with a code like following
#include
#include
void foo(int* p)
{
*p = 5;
printf("\n Inside foo() the value of the variable: %d",*p);
}
int main(void)
{
int i = 10;
printf("\n before calling foo() the value of the variable: %d",i);
foo(&i);
printf("\n after calling foo() the value of the variable: %d",i);
getch();
return 0;
}
Your code will show the result as
Your points are well taken. But the thing is what you are showing is not at all calling a function by reference. It just the function call by value! Here you are essentially copying the value of address of your variable i and calling the function foo with that copy. Now eventually in this case, the value that is being passed contains the address of another variable. Within the function, you are accepting this value with a pointer and changing the value of the content addressed by that pointer. So it is nothing but a function call by value only.
Please note that to change the value of the content addressed by a pointer, you are to use *, no way could it be thought of as a reference.
Now let me give you one example of true function call by reference
#include
#include
void foo (int& r1)
{
r1 = 5;
printf("\n Inside foo() the value of the variable: %d", r1);
}
int main(void)
{
int i = 10;
int &r = i;
printf("\n before calling foo() the value of the variable: %d",i);
foo(r);
printf("\n after calling foo() the value of the variable: %d",i);
getch();
return 0;
}
Will this run with your C compiler? No.
Note:: I have used DevC++ as the coding platform
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Lesson Posted on 05/07/2017 Learn BTech Information Science Engineering
Some Interview Questions And Answers For Fresher Level On Pointers
Shiladitya Munshi
Well, I love spending time with students and to transfer whatever computing knowledge I have acquired...
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Answered on 12/02/2017 Learn BTech Information Science Engineering
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