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Learn Exercise 5.2 with Free Lessons & Tips

Convert the given complex number in polar form: i

i

Let r cosθ = 0 and r sin θ = 1

On squaring and adding, we obtain

This is the required polar form.

Comments

Find the modulus and the argument of the complex number

 

On squaring and adding, we obtain

Since both the values of sin θ and cos θ are negative and sinθ and cosθ are negative in III quadrant,

Thus, the modulus and argument of the complex number are 2 and respectively.

Comments

Find the modulus and the argument of the complex number

 

On squaring and adding, we obtain

Thus, the modulus and argument of the complex number are 2 and respectively.

Comments

Convert the given complex number in polar form: 1 – i

1 – i

Let r cos θ = 1 and r sin θ = –1

On squaring and adding, we obtain

This is the required polar form.

Comments

Convert the given complex number in polar form: – 1 + i

– 1 + i

Let r cos θ = –1 and r sin θ = 1

On squaring and adding, we obtain

It can be written,

This is the required polar form.

Comments

Convert the given complex number in polar form: – 1 – i

– 1 – i

Let r cos θ = –1 and r sin θ = –1

On squaring and adding, we obtain

This is the required polar form.

Comments

Convert the given complex number in polar form: –3

 

–3

Let r cos θ = –3 and r sin θ = 0

On squaring and adding, we obtain

This is the required polar form.

Comments

Convert the given complex number in polar form:

Let r cos θ = and r sin θ = 1

On squaring and adding, we obtain

This is the required polar form.

Comments

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