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If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons would flow through the wire?
I = 0.5 A
t = 2 hours = 2 × 60 × 60 s = 7200 s
Thus, Q = It
= 0.5 A × 7200 s
= 3600 C
We know that _17-11-08_Utpal_12_Chemistry_3_15_html_1bc29ed2.gif){kind=small}
number of electrons.
Then,
_17-11-08_Utpal_12_Chemistry_3_15_html_202941eb.gif)
Hence, _17-11-08_Utpal_12_Chemistry_3_15_html_3c6201b9.gif){kind=small}
number of electrons will flow through the wire.
Suggest a list of metals that are extracted electrolytically.
Metals that are on the top of the reactivity series such as sodium, potassium, calcium, lithium, magnesium, aluminium are extracted electrolytically.
Consider the reaction:_17-11-08_Utpal_12_Chemistry_3_15_html_5c5cd94a.gif){kind=small}
What is the quantity of electricity in coulombs needed to reduce 1 mol of
_17-11-08_Utpal_12_Chemistry_3_15_html_m1d462c49.gif){kind=small}
?
The given reaction is as follows:
Therefore, to reduce 1 mole of , the required quantity of electricity will be:
=6 F
= 6 × 96487 C
= 578922 C
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