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(a) Bond angle in PH4 + is higher than that in PH3. Why? (b) What is formed when PH3 reacts with an acid?
In PH3, P is sp3 hybridized. Three orbitals are involved in bonding with three hydrogen atoms and the fourth one contains a lone pair. As lone pair-bond pair repulsion is stronger than bond pair-bond pair repulsion, the tetrahedral shape associated with sp3 bonding is changed to pyramidal. PH3 combines with a proton to form 
in which the lone pair is absent. Due to the absence of lone pair in, there is no lone pair-bond pair repulsion. Hence, the bond angle in is higher than the bond angle in PH3.
What happens when white phosphorus is heated with concentrated NaOH solution in an inert atmosphere of CO2 ?
White phosphorous dissolves in boiling NaOH solution (in a CO2 atmosphere) to give phosphine, PH3.
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