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Evaluate the definite integrals
∫(x+1)dx=∫xdx+∫1dx= (x^2/2)+x+C
Definite intergal = [(x^2/2)+x]1-1
=[1^2/2+1]-[(-1)^2/2-1]
=[3/2]-[-1/2]
=3/2+1/2=4/2=2
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
By second fundamental theorem of calculus, we obtain
Evaluate the definite integrals
Evaluate the definite integrals
Let 
Equating the coefficients of x and constant term, we obtain
A = 10 and B = −25
Substituting the value of I1 in (1), we obtain
Evaluate the definite integral
By second fundamental theorem of calculus, we obtain
Evaluate the definite integral
By second fundamental theorem of calculus, we obtain
Evaluate the definite integral
By second fundamental theorem of calculus, we obtain
Evaluate the definite integral
By second fundamental theorem of calculus, we obtain
equals
A. 
B. 
C. 
D. 
By second fundamental theorem of calculus, we obtain
Hence, the correct answer is D.
equals
A. 
B. 
C. 
D. 
By second fundamental theorem of calculus, we obtain
Hence, the correct answer is C.
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