Find the best tutors and institutes for Class 6 Tuition
Search in
Find the areas of the rectangles whose sides are:
(a) 3 cm and 4 cm (b) 12 m and 21 m
(c) 2 km and 3 km (d) 2 m and 70 cm
It is known that,
Area of rectangle = Length × Breadth
(a) l = 3 cm
b = 4 cm
Area = l × b = 3 × 4 = 12 cm2
(b) l = 12 m
b = 21 m
Area = l × b = 12 × 21 = 252 m2
(c) l = 2 km
b = 3 km
Area = l × b = 2 × 3 = 6 km2
(d) l = 2 m
b = 70 cm = 0.70 m
Area = l × b = 2 × 0.70 = 1.40 m2
Find the areas of the squares whose sides are:
(a) 10 cm (b) 14 cm (c) 5 m
It is known that,
Area of square = (Side)2
(a) Side = 10 cm
Area = (10)2 =100 cm2
(b) Side = 14 cm
Area = (14)2 = 196 cm2
(c) Side = 5 m
Area = (5)2 = 25 m2
The length and breadth of three rectangles are as given below:
(a) 9 m and 6 m (b) 17 m and 3 m (c) 4 m and 14 m
Which one has the largest area and which one has the smallest?
It is known that,
Area of rectangle = Length × Breadth
(a) l = 9 m
b = 6 m
Area = l × b = 9 × 6 = 54 m2
(b) l = 17 m
b = 3 m
Area = l × b = 17 × 3 = 51 m2
(c) l = 4 m
b = 14 m
Area = l × b = 4 × 14 = 56 m2
It can be seen that rectangle (c) has the largest area and rectangle (b) has the smallest area.
A room is 4 m long and 3 m 50 cm wide. How many square metres of carpet is needed to cover the floor of the room?
Length (l) = 4 m
Breadth (b) = 3 m 50 cm = 3.5 m
Area = l × b = 4 × 3.5 = 14 m2
A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.
Length (l) = 5 m
Breadth (b) = 4 m
Area of floor = l × b = 5 × 4 = 20 m2
Area covered by the carpet = (Side)2 = (3)2 = 9 m2
Area not covered by the carpet = 20 − 9 = 11 m2
Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?
Area of the land = 5 × 4 = 20 m2
Area occupied by 5 flower beds = 5 × (Side)2 = 5 × (1)2 = 5 m2
∴ Area of the remaining part = 20 − 5 = 15 m2
The area of a rectangular garden 50 m long is 300 sq m. Find the width of the garden.
Let the breadth of the rectangular garden be b.
l = 50 m
Area = l × b = 300 square m
50 × b = 300
b = 
What is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of Rs 8 per hundred sq m?
Area of rectangular plot = 500 × 200 = 100000 m2
Cost of tiling per 100 m2 = Rs 8
Cost of tiling per 100000 m2 =
= Rs 8000
A table-top measures 2 m by 1 m 50 cm. What is its area in square metres?
Length (l) = 2 m
Breadth (b) = 1 m 50 cm =
Area = l × b = 2 × 1.5 = 3 m2
By splitting the following figures into rectangles, find their areas (The measures are given in centimetres).
(a) (b)
(a) The given figure can be broken into rectangles as follows.
Area of 1st rectangle = 4 × 2 = 8 cm2
Area of 2nd rectangle = 6 × 1 = 6 cm2
Area of 3rd rectangle = 3 × 2 = 6 cm2
Area of 4th rectangle = 4 × 2 = 8 cm2
Total area of the complete figure = 8 + 6 + 6 + 8 = 28 cm2
(b) The given figure can be broken into rectangles as follows.
Area of 1st rectangle = 3 × 1 = 3 cm2
Area of 2nd rectangle = 3 × 1 = 3 cm2
Area of 3rd rectangle = 3 × 1 = 3 cm2
Total area of the complete figure = 3 + 3 + 3 = 9 cm2
Split the following shapes into rectangles and find their areas. (The measures are given in centimetres)
(a) The given figure can be broken into rectangles as follows.
Area of 1st rectangle = 12 × 2 = 24 cm2
Area of 2nd rectangle = 8 × 2 = 16 cm2
Total area of the complete figure = 24 + 16 = 40 cm2
(b) The given figure can be broken into rectangles as follows.
Area of 1st rectangle = 21 × 7 = 147 cm2
Area of 2nd square = 7 × 7 = 49 cm2
Area of 3rd square = 7 × 7 = 49 cm2
Total area of the complete figure = 147 + 49 + 49 = 245 cm2
(c) The given figure can be broken into rectangles as follows.
Area of 1st rectangle = 5 × 1 = 5 cm2
Area of 2nd rectangle = 4 × 1 = 4 cm2
Total area of the complete figure = 5 + 4 = 9 cm2
How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively:
(a) 100 cm and 144 cm
(b) 70 cm and 36 cm
(a) Total area of the region = 100 × 144 = 14400 cm2
Area of one tile = 12 × 5 = 60 cm2
Number of tiles required =
Therefore, 240 tiles are required.
(b) Total area of the region = 70 × 36 = 2520 cm2
Area of one tile = 60 cm2
Number of tiles required =
Therefore, 42 tiles are required.
How helpful was it?
How can we Improve it?
Please tell us how it changed your life *
Please enter your feedback
UrbanPro.com helps you to connect with the best Class 6 Tuition in India. Post Your Requirement today and get connected.
Find best tutors for Class 6 Tuition Classes by posting a requirement.
Get started now, by booking a Free Demo Class
