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Learn Exercise 2.2 with Free Lessons & Tips

Find the product using suitable properties.

(a) 738 × 103 (b) 854 × 102

(c) 258 × 1008 (d) 1005 × 168

a) 738 x 103

738 x (100 +3)

(738x100) + (738 x3).  ( distributive property)

73800 + 2214

76014

Comments

Find the sum by suitable rearrangement:

(a) 837 + 208 + 363 (b) 1962 + 453 + 1538 + 647

a) (837+208)+363

1045+363 = 1408

b) (1962+453) + (1538+647)

       2415 + 2185 = 4600

 

Comments

Find the product by suitable rearrangement:

(a) 2 × 1768 × 50 (b) 4 × 166 × 25

(c) 8 × 291 × 125 (d) 625 × 279 × 16

(e) 285 × 5 × 60 (f) 125 × 40 × 8 × 25

(a) 2 × 1768 × 50 = 2 × 50 × 1768

= 100 × 1768 = 1,76,800

(b) 4 × 166 × 25 = 4 × 25 × 166

= 100 × 166 = 16,600

(c) 8 × 291 × 125 = 8 × 125 × 291

= 1000 × 291 = 2,91,000

(d) 625 × 279 × 16 = 625 × 16 × 279

= 10000 × 279 = 27,90,000

(e) 285 × 5 × 60 = 285 × 300 = 85,500

(f) 125 × 40 × 8 × 25 = 125 × 8 × 40 × 25

= 1000 × 1000 = 10,00,000

Comments

Find the value of the following:

(a) 297 × 17 + 297 × 3 (b) 54279 × 92 + 8 × 54279

(c) 81265 × 169 − 81265 × 69 (d) 3845 × 5 × 782 + 769 × 25 × 218

(a) 297 × 17 + 297 × 3 = 297 × (17 + 3)

= 297 × 20 = 5940

(b) 54279 × 92 + 8 × 54279 = 54279 × 92 + 54279 × 8

= 54279 × (92 + 8)

= 54279 × 100 = 54,27,900

(c) 81,265 × 169 − 81,265 × 69 = 81,265 × (169 − 69)

= 81265 × 100 = 81,26,500

(d) 3845 × 5 × 782 + 769 × 25 × 218

= 3845 × 5 × 782 + 769 × 5 × 5 × 218

= 3845 × 5 × 782 + 3845 × 5 × 218

= 3845 × 5 × (782 + 218)

= 19,225 × 1000 = 1,92,25,000

Comments

A taxi driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs Rs 44 per litre, how much did he spend in all on petrol?

Petrol filled in a car on 1st day = 40 L

Petrol filled in a car on 2nd day = 50 L

Total petrol filled in a car = (40+50)L = 90L

Cost of 1 L petrol = 44 rs.

Cost of 90 L petrol = 90 x 44 = Rs. 3960

Therefore, he spend Rs. 3960 in all on petrol

Comments

A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs Rs 15 per litre, how much money is due to the vendor per day?

Quantity of milk supplied in the morning = 32 l

Quantity of milk supplied in the evening = 68 l

Total of milk per litre = (32 + 68) l

Cost of milk per litre = Rs 15

Total cost per day = 15 × (32 + 68)

= 15 × 100 = Rs 1500

Comments

Match the following:

(i) 425 × 136 = 425 × (6 + 30 + 100)

(a) Commutativity under multiplication

(ii) 2 × 49 × 50 = 2 × 50 × 49

(b) Commutativity under addition

(iii) 80 + 2005 + 20 = 80 + 20 + 2005

(c) Distributivity of multiplication over addition

(i) 425 × 136 = 425 × (6 + 30 + 100) [Distributivity of multiplication over addition]

Hence, (c)

(ii) 2 × 49 × 50 = 2 × 50 × 49 [Commutativity under multiplication]

Hence, (a)

(iii) 80 + 2005 + 20 = 80 + 20 + 2005 [Commutativity under addition]

Hence, (b)

Comments

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