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Find the probabilities of the events given When a die is thrown, list the outcomes of an event of getting (i) (a) a prime number (b) not a prime number (ii) (a) a number greater than 5 (b) a number not greater than 5.
(i) (a) Out of 6 possible outcomes, a prime number can be obtained in three cases. Therefore, probability of getting a prime number = 
(b) Out of 6 possible outcomes, a prime number may not be obtained in three cases.
Therefore, probability of getting not a prime number =
(ii) (a) Out of 6 possible outcomes, a number greater than 5 can be obtained in only 1 case.
Therefore, probability of getting a number greater than 5 = 
(b) Out of 6 possible outcomes, a number not greater than 5 can be obtained in 5 cases.
Therefore, probability of getting a number not greater than 5 = 
List the outcomes you can see in these experiments.
(a) Spinning a wheel
(b) Tossing two coins together
(a) On spinning the given wheel, the possible outcomes are A, B, C, D.
(b) By tossing two coins together, the possible outcomes are HT, TH, HH, TT where H and T represents Head and Tail of the coins respectively.
When a die is thrown, list the outcomes of an event of getting
(i) (a) a prime number (b) not a prime number
(ii) (a) a number greater than 5 (b) a number not greater than 5
When a dice is thrown, the possible outcomes are 1, 2, 3, 4, 5, and 6.
(i) (a) Out of these outcomes, 2, 3, 5 are prime numbers. Hence, these are the outcomes of an event of getting a prime number on the face of a dice.
(b) Out of these outcomes, 1, 4, 6 are not prime numbers. Hence, these are the outcomes of an event of not getting a prime number on the face of a dice.
(ii) (a) Out of these outcomes, a number greater than 5 is possible when 6 comes on the face of the dice.
(b) Out of these outcomes, a number not greater than 5 is possible when the number on the face of the dice is any one of the outcomes 1, 2, 3, 4, 5.
Find the.
(a) Probability of the pointer stopping on D in (Question 1 − (a))?
(b) Probability of getting an ace from a well shuffled deck of 52 playing cards?
(c) Probability of getting a red apple. (See figure below)
(i) The pointer can stop at one of the following regions.
A, A, B, C, D
Out of these 5 cases, it is possible only in 1 case that the pointer will stop at region D.
Therefore, probability that the pointer will stop at region D = 
(ii) There are 52 cards in a deck of cards and there are 4 ace cards in 1 deck of cards.
Probability of getting an ace card = 
(iii) There are a total of 7 apples, out of which, 4 are red and 3 are green.
Probability of getting a red apple = 
Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of.
(i) getting a number 6?
(ii) getting a number less than 6?
(iii) getting a number greater than 6?
(iv) getting a 1-digit number?
(i) There are 10 slips in the box. However, 6 is written only on 1 slip.
Probability of getting a number 6 = 
(ii) The numbers less than 6 are 1, 2, 3, 4, 5.
Probability of getting a number less than 6 = 
(iii) The numbers greater than 6 are 7, 8, 9, 10.
Probability of getting a number greater than 6 = 
(iv) There are 9 numbers which are single digit numbers.
1, 2, 3, 4, 5, 6, 7, 8, 9
Probability of getting a single digit number = 
If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non blue sector?
number of green sectors=3
number of blue sectors=1
number of red sectors=1
probability of getting a green sector=number of green sector/total number of sectors
=3/5
number of non blue sectors=number of green sectors+number of red sectors=3+1=4
probability of getting non blue sector=number of non blue sectors/total number of sectors
=4/5
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