Jankipuram, Lucknow, India - 226021
Verified 6
Details verified of Pankaj Shukla✕
Identity
Education
Know how UrbanPro verifies Tutor details
Identity is verified based on matching the details uploaded by the Tutor with government databases.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
10
Board
ICSE
Preferred class strength
One on one/ Private Tutions
ICSE Subjects taught
Biology, Physics, Chemistry
Taught in School or College
Yes
Teaching Experience in detail in Class 10 Tuition
š Unlock Your Academic Potential with Pankaj Shukla's Tuition Classes! š š Subjects Offered: Class 10: Physics, Chemistry, Mathematics, Biology Class 11,12: Chemistry, Biology š Features: Expert guidance for ICSE/CBSE curriculum Proven track record of success Small class sizes for personalized attention š° Pricing: Class 10: ā¹3000 per subject (Minimum two subjects) Class 11,12: ā¹6500 per subject šļø Next Session Starting April 2024!
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
12
NIOS Subjects taught
Chemistry, Biotechnology, Biology
Board
ISC/ICSE, NIOS, CBSE
Preferred class strength
One on one/ Private Tutions
ISC/ICSE Subjects taught
Chemistry, Biology
CBSE Subjects taught
Biology, Biotechnology, Chemistry
Taught in School or College
Yes
Teaching Experience in detail in Class 12 Tuition
Teaching class 11 and 12 chemistry and Biology since last 12 years š Unlock Your Academic Potential with Pankaj Shukla's Tuition Classes! š š Subjects Offered: Class 10: Physics, Chemistry, Mathematics, Biology Class 11,12: Chemistry, Biology š Features: Expert guidance for ICSE/CBSE curriculum Proven track record of success Small class sizes for personalized attention š° Pricing: Class 10: ā¹3000 per subject (Minimum two subjects) Class 11,12: ā¹6500 per subject šļø Next Session Starting April 2024!
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
10
Board
IGCSE, ISC/ICSE, CBSE
Preferred class strength
One on one/ Private Tutions
ISC/ICSE Subjects taught
Chemistry, Biology
CBSE Subjects taught
Biology, Biotechnology, Chemistry
IGCSE Subjects taught
Biology, Chemistry
Taught in School or College
Yes
Teaching Experience in detail in Class 11 Tuition
Teaching class 11 and 12 chemistry and biology since last 10 years
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
14
Board
ICSE
Preferred class strength
One on one/ Private Tutions
ICSE Subjects taught
Biology, Physics, Chemistry
Taught in School or College
Yes
Teaching Experience in detail in Class 9 Tuition
Teaching with a Difference ! Stepping Stone for Foundation of IIT/NEET. Weekly & Monthly Test, Complete Course Completion till Nov and twice Revision of Course in case of ICSE and CBSE
5 out of 5 2 reviews
Ashish Saxena
"Pankaj mode of teaching is quite interactive and unique. He not only explain the concepts in a simplified way but also inculcate interest in the subject. Just to underline that he is not a professional teacher but teaching is his passion. I highly recommend parents to request his mentorship for his child. At last I will add that he is not a teacher but also a very good career counselor. "
Ashish Saxena
"Pankaj Sir is the best and because of his efforts I got 99 % in physics, chemistry and Biology. He makes student visualize the topic. Amazing way of teaching chemistry. Organic is the best. "
Answered on 11/10/2018 Learn CBSE/Class 11/Science/Chemistry
Answered on 17/09/2018 Learn CBSE/Class 11/Science/Physics/Unit 3-Laws of Motion/Chapter 5-Laws of Motion
Speed of the water stream, v = 15 m/s
Cross-sectional area of the tube, A = 10–2 m2
Volume of water coming out from the pipe per second,
V = Av = 15 × 10–2 m3/s
Density of water, ρ = 103 kg/m3
Mass of water flowing out through the pipe per second = ρ × V = 150 kg/s
The water strikes the wall and does not rebound. Therefore, the force exerted by the water on the wall is given by Newton’s second law of motion as:
F = Rate of change of momentum = ?P / ?t
= mv / t
= 150 × 15 = 2250 N
Answered on 22/04/2017 Learn Tuition/Class VI-VIII Tuition
Answered on 22/04/2017 Learn Tuition/Class VI-VIII Tuition
Share this Profile
Also have a look at
Reply to 's review
Enter your reply*
Your reply has been successfully submitted.
Certified
The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.