NCERT Solutions for Class 6 Maths, Chapter 10 - Mensuration

In NCERT Maths Book Class 6, Chapter 10 Solutions, as you progress through the chapter you will learn mensuration. When we talk about some plane figures we think of their regions and their boundaries. We need some measures to compare them. As you move further in this chapter you will study the concept of the perimeter with the help of examples of the perimeter of rectangles and regular shapes. Further, you will study areas of rectangle and square.

Let’s take a look at topics and sub-topics of Class 6 Maths Chapter 10, Mensuration

10.1 Introduction

10.2 Perimeter

              10.2.1 Perimeter Of A Rectangle

              10.2.2 Perimeter Of Regular Shapes

10.3 Area

              10.3.1 Area Of A Rectangle

              10.3.2 Area Of  A Square

In Class 6 Maths NCERT Solutions Chapter 10, you will learn –

Section 10.2 – This section will brief you about the concept of perimeter. It is basically the distance covered along the boundary forming a closed figure when you go around the figure once. Let us consider a rectangle ABCD whose length and breadth are 15 cm and 9 cm respectively. What will be its perimeter? The perimeter of the rectangle = Sum of the lengths of its four sides. = AB + BC + CD + DA = AB + BC + AB + BC = 2 × AB + 2 × BC = 2 × (AB + BC) = 2 × (15cm + 9cm) = 2 × (24cm) = 48 cm. Hence, from the said example, we notice that Perimeter of a rectangle = length + breadth + length + breadth i.e. Perimeter of a rectangle = 2 × (length + breadth). As you move further in this section you will study the perimeter of regular shapes. Consider this example. Biswamitra wants to put coloured tape all around a square picture of side 1m. What will be the length of the coloured tape he requires? Since Biswamitra wants to put the coloured tape all around the square picture, he needs to find the perimeter of the picture frame. Thus, the length of the tape required = Perimeter of square = 1m + 1 m + 1 m + 1 m = 4 m.  Now, we know that all the four sides of a square are equal, therefore, in place of adding it four times, we can multiply the length of one side by 4. Thus, the length of the tape required = 4 × 1 m = 4 m. From this example, we see that Perimeter of a square = 4 × the length of a side. Similarly, the perimeter of an equilateral triangle = 3 × the length of a side.

Section 10.3 – Towards the end of this chapter this section will brief you about the concept of areas. The amount of surface enclosed by a closed figure is called its area. To calculate the area of a figure using a squared paper, the following conventions are adopted : (a) Ignore portions of the area that are less than half a square. (b) If more than half a square is in a region. Count it as one square. (c) If exactly half the square is counted, take its area as 1/2 sq units. Consider an example, draw the rectangle on a graph paper having 1 cm × 1 cm squares. The rectangle covers 15 squares completely. The area of the rectangle = 15 sq cm which can be written as 5 × 3 sq cm i.e. (length × breadth). As you move further in this section you will study how to find the area of a square. Consider an example, If we place it on a centimetre graph paper, then what do we observe? It covers 16 squares i.e. the area of the square = 16 sq cm = 4 × 4 sq cm Calculate areas of few squares by assuring length of one side of squares by yourself. Find their areas using graph papers. What do we infer from this? We find that in each case, Area of the square = side × side.

In this chapter, you are provided with several examples along with their solutions for a clear understanding of mensuration. To know more about NCERT Solutions for Class 6 Maths Chapter 10 Mensuration, you should explore the exercises below. You can also download the mensuration Class 6 NCERT Solutions PDF, solved by expert maths trainers. You can also refer online to Class 6 Maths Chapter 10 Worksheet PDF.